Option 20 IDZ 2.1

IDZ – 2.1 No. 1.20.

Given vectors a = α·m + β·n; b = γ m + δ n; |m| = k; |n| = ℓ; (m;n) = φ; Find:

а) ( λ·a + μ·b );( ν·a + τ·b );

b) projection ( ν·a + τ·b ) onto b;

в) cos( a + τ·b ).

Dano: α = 3; β = -5; γ =-2; d = 3; k = 1; ℓ = 6; φ = 3π/2; λ = 4; μ = 5; n = 1; τ = -2.

№ 2.20.

By coordinates of points A; B and C for the indicated vectors find:

a) modulus of vector a;

b) scalar product of vectors a and b;

c) projection of vector c onto vector d;

d) coordinates of the point M dividing the segment ℓ in relation to α:

Hopefully: A(5;4;4 ); B(–5;2;3);C(4;2;– 5 ); …….

№ 3.20.

Prove that vectors a;b;c form a basis and find the coordinates of vector d in this basis.

Hopefully: a(11;1;2 ); b(–3;3;4); c(–4;–2; 7 ); d(–5; 11;–15 )

IDZ – 2.1 No. 1.20. For given vectors $a = \alpha\cdot m + \beta\cdot n$ and $b = \gamma\cdot m + \delta\cdot n$, where $|m| = k$, $|n| = \ell$, and $(m;n) = \varphi$, you need to find:

а) $(\lambda\cdot a + \mu\cdot b)\cdot(\nu\cdot a + \tau\cdot b)$;

b) projection of the vector $\nu\cdot a + \tau\cdot b$ onto the vector $b$;

в) $\cos(a + \tau\cdot b)$.

It is known that $\alpha = 3$, $\beta = -5$, $\gamma = -2$, $\delta = 3$, $k = 1$, $\ell = 6$, $\varphi = \frac{3\pi}{2}$, $\lambda = 4$, $\mu = 5$, $\nu = 1$, and $\tau = -2$.

No. 2.20. For vectors specified by the coordinates of points $A(5;4;4)$, $B(-5;2;3)$, and $C(4;2;-5)$, it is necessary to find:

a) modulus of vector $a$;

b) scalar product of vectors $a$ and $b$;

c) projection of vector $c$ onto vector $d$;

d) coordinates of the point $M$ dividing the segment $\ell$ in relation $\alpha$.

No. 3.20. Prove that the vectors $a$, $b$, and $c$ form a basis and find the coordinates of the vector $d$ in this basis. It is known that $a(11;1;2)$, $b(-3;3;4)$, $c(-4;-2;7)$, and $d(-5;11;-15 ).

"Option 20 IDZ 2.1" is a digital product designed for students studying linear algebra. It contains a detailed description of the solution to three vector problems, as well as the given initial data needed to solve them. The product is designed in a beautiful html format, which ensures ease of reading and ease of perception of information. In addition, thanks to the digital format, the product can be purchased and downloaded at any convenient time and place, and also used on different devices without losing display quality. "Option 20 IDZ 2.1" is an excellent choice for students who want to deepen their knowledge in linear algebra and successfully complete assignments in this discipline.

Option 20 IDZ 2.1 is a digital product containing solutions to three problems in linear algebra.

In the first problem, vectors a and b are given, specified through their coefficients and basis vectors m and n, and the values ​​λ, μ, ν and τ are also given. It is necessary to find: a) the value of the scalar product of the vectors ( λ·a + μ·b ) and ( ν·a + τ·b ); b) projection of the vector ( ν·a + τ·b ) onto the vector b; c) the value of the cosine of the angle between vectors a and a + τ·b.

In the second problem, the coordinates of three points A, B and C are given, and you need to find: a) the magnitude of the vector given by the coordinates of points A and B; b) the scalar product of vectors specified by the coordinates of points A and B, and the coordinates of points A and C; c) projection of the vector specified by the coordinates of points C and D onto the vector specified by the coordinates of points A and B; d) coordinates of the point M dividing the segment AB in relation to α.

In the third problem, you need to prove that vectors a, b and c form a basis in three-dimensional space, and find the coordinates of vector d in this basis.

The product is designed in an easy-to-read HTML format and contains all the necessary initial data and a step-by-step description of how to solve problems. "Option 20 IDZ 2.1" is an excellent choice for students who want to deepen their knowledge in linear algebra and successfully complete assignments in this discipline.


***


IDZ 2.1 No. 1.20 is a task that includes several points to be solved using these vectors and coefficients:

Given vectors a = α·m + β·n; b = γ m + δ n; |m| = k; |n| = ℓ; (m;n) = φ;

where α = 3; β = -5; γ =-2; d = 3; k = 1; ℓ = 6; φ = 3π/2;

Need to find:

а) ( λ·a + μ·b );( ν·a + τ·b );

b) projection ( ν·a + τ·b ) onto b;

в) cos( a + τ·b ).

To solve the problem you must complete the following steps:

  1. Calculate vectors a and b using the given coefficients and vectors m and n.

  2. Calculate λ·a + μ·b and ν·a + τ·b using these coefficients.

  3. Find the scalar product ( λ·a + μ·b )·( ν·a + τ·b ).

  4. Find the projection of the vector ν·a + τ·b onto the vector b.

  5. Find cos( a + τ·b ) using the formula cos( a + τ·b ) = cos a · cos τ·b + sin a · sin τ·b.

The solution to the task might look like this:

  1. a = 3·m - 5·n; b = -2·m + 3·n;

  2. λ·a + μ·b = 4·a + 5·b = (12m - 20n) + (-10m + 15n) = 2m - 5n;

    ν·a + τ·b = 1·a - 2·b = (3m - 5n) - (-4m + 6n) = 7m - 11n;

  3. ( λ·a + μ·b );( ν·a + τ·b ) = (2m - 5n)·(7m - 11n) = 14m^2 - 77mn + 55n^2;

  4. The projection of the vector 7m - 11n onto the vector -2m + 3n is equal to ((7m - 11n)·(-2m + 3n))/(-2^2 + 3^2) = (-29m - 13n)/13;

  5. cos( a + τ·b ) = cos a · cos τ·b + sin a · sin τ·b = ((3m - 5n)·(-2) + (2m - 3n)·1)/(√(9 +25·√(4+9)) = -11/13.


***


  1. This digital product is convenient and ships quickly.
  2. The quality of this digital product is at a high level.
  3. Thanks to this digital product I save a lot of time and effort.
  4. I am pleased that I purchased this digital product, it fully meets my expectations.
  5. This digital product has helped me solve many problems and save money.
  6. I can no longer imagine my life without this digital product.
  7. This digital product is an indispensable tool in my work.
  8. I recommend this digital product to all my friends and colleagues.
  9. This digital product is easy to use and has many useful features.
  10. Thanks to this digital product, I get fast and high-quality results.



Peculiarities:




A digital product is convenient and saves time, there is no need to look for a store and waste time on a trip.

Great quality digital goods - all files were crisp and ready to use.

A very simple process of buying and receiving a digital product.

The digital product was available for download instantly after payment.

Large selection of digital goods, which allows you to find exactly what you need.

A digital product is the best solution for those who want to quickly get the material they need.

A digital good is a reliable and secure way to obtain information or a product.

It is very convenient that a digital product can be downloaded and stored on a computer or other device for future use.

The digital product is an environmentally friendly solution that does not create packaging waste or paper instructions.

A digital product is a great choice for those who want to save money and get a quality product.

Related Products

Additional Information

Rating: 4.6
(95)