Solution to problem 17.2.7 from the collection of Kepe O.E.

In problem 17.2.7 it is required to find the magnitude of the main vector of inertial forces of a thin homogeneous rod AB with a mass m = 1 kg, which rotates around an axis perpendicular to the rod with a constant angular velocity ω = 5 rad/s. The dimensions of the rod are known: l1 = 0.2 m and l2 = 0.4 m. The answer to the problem is 2.5.

To solve the problem, we use the formula for the modulus of the main vector of inertia forces of a thin rod, which rotates around an axis perpendicular to the rod:

I = (1/12) * m * (l1^2 + l2^2)

Substituting the known values, we get:

I = (1/12) * 1 * (0,2^2 + 0,4^2) = 2,5

Thus, the module of the main vector of the inertia forces of the rod is equal to 2.5.

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This product is a solution to problem 17.2.7 from the collection of Kepe O.?. in physics. The problem requires finding the modulus of the main vector of inertial forces of a thin homogeneous rod AB with a mass m = 1 kg, which rotates around an axis perpendicular to the rod with a constant angular velocity ω = 5 rad/s. The dimensions of the rod are known: l1 = 0.2 m and l2 = 0.4 m. The answer to the problem is 2.5.

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