Solution to problem 14.2.7 from the collection of Kepe O.E.

Consider the problem: pulley 1 has a radius R = 0.4 m and rotates with an angular velocity ω = 2.5 rad/s. A load 2 with a mass m = 10 kg is suspended on a pulley. It is necessary to determine the modulus of momentum of the load.

To solve this problem, we use the law of conservation of momentum:

p = mv,

where p is the momentum, m is the mass of the body, v is its speed.

Since the system is at rest vertically, the speed of the load is 0. Therefore, the module of the momentum of the load is equal to:

p = mv = 10 kg * 0 m/s = 0 kg m/s.

Answer: 0 kg m/s.

Solution to problem 14.2.7 from the collection of Kepe O..

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Our product contains a detailed solution to the problem using the law of conservation of momentum and the answer to the question, what is the modulus of momentum of a 10 kg load raised to a height of 2 meters.

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Our digital product is a convenient and affordable solution for all students and teachers who want to get a complete and accurate solution to problem 14.2.7 from the collection of Kepe O..

We present to your attention a digital product - a solution to problem 14.2.7 from the collection of Kepe O.?. The problem describes the movement of a load suspended on a pulley, which rotates with an angular velocity ω = 2.5 rad/s. Our product contains a detailed solution to the problem using the law of conservation of momentum and the answer to the question, what is the modulus of momentum of a 10 kg load raised to a height of 2 meters.

To solve this problem, we use the law of conservation of momentum: p = mv, where p is the momentum, m is the mass of the body, v is its speed. Since the system is at rest vertically, the speed of the load is 0. Therefore, the module of the momentum of the load is equal to: p = mv = 10 kg * 0 m/s = 0 kg m/s.

Our digital product is a convenient and affordable solution for all students and teachers who want to get a complete and accurate solution to problem 14.2.7 from the collection of Kepe O.?. You can purchase our solution to the problem in the format of a digital product that can be easily downloaded and used for educational purposes or to prepare for exams.

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Solution to problem 14.2.7 from the collection of Kepe O.?. consists in determining the modulus of momentum of the load, which is lifted by pulley 1 of radius R = 0.4 m with an angular velocity si = 2.5 rad/s. The load has mass m = 10 kg.

The modulus of momentum of a load is defined as the product of its mass and speed:

p = m * v

To solve the problem, you need to determine the speed of the load that is lifted by the pulley. To do this, we use the law of conservation of energy:

Ep = ?к

where Ep is the potential energy of the load at the lifting height h, ?к is the kinetic energy of the load at the moment it reaches speed v.

The potential energy of the load at the lifting height h is equal to:

Eп = m * g * h

where g is the acceleration of gravity, we take it equal to 9.81 m/s^2.

The kinetic energy of the load at the moment of reaching speed v is equal to:

?к = (m * v^2) / 2

The law of conservation of energy can be written as:

m * g * h = (m * v^2) / 2

Solving this equation for v, we get:

v = sqrt(2 * g * h)

h in this problem is equal to the radius of the pulley R on which the load is lifted:

h = R = 0.4 м

Then:

v = sqrt(2 * g * R) = sqrt(2 * 9.81 * 0.4) ≈ 2.79 m/s

Now you can find the modulus of the momentum of the load:

p = m * v = 10 * 2.79 ≈ 27.9 Н*с

Answer: 27.9 N*s (rounded to one decimal place).

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