On the edge of a circular platform with radius R = 2.35 m

A washer lies on a circle of radius R = 2.35 m. The platform begins to rotate so that the path traveled by the puck increases in accordance with the equation s = Ct^2, where C = 0.5 m/s^2. It is necessary to determine the moment in time when the washer begins to slide off the platform if the coefficient of friction is 0.2.

To solve the problem we use the law of conservation of energy. Initially, the washer is at height R. When the washer moves in a circle, its potential energy is converted into kinetic energy. When the puck reaches the sliding point, its kinetic energy will be equal to the work done by the friction force, in other words, the energy loss due to friction. Thus, we have the equation:

mgR = (1/2)mv^2 + Ftr*s,

where m is the mass of the puck, g is the acceleration of gravity, v is the speed of the puck, Ftr is the friction force, s is the path traveled by the puck.

Considering that s = Ct^2, Ftr = inmg, where mu is the friction coefficient, and rewriting the equation for Newton’s second law of motion in a circle, we obtain:

mRC^2 = usmg*R - (1/2)mv^2.

Solving the equation for time t, we get:

t = sqrt(2muR/g).

Substituting numerical values, we get:

t = sqrt(20.22.35/9.81) ≈ 0.318 s.

Thus, the puck will begin to slide off the platform approximately 0.318 seconds after the platform begins to rotate.

This digital product is a true masterpiece among digital product stores! It is a fun physics problem that will test your knowledge and skills in this field.

The HTML design of the product is made in a beautiful and laconic style, which makes viewing the page as convenient and enjoyable as possible. On the product page you will find a description of the problem, which begins with an image of a circular platform of radius R = 2.35 m, on the edge of which lies a washer.

This page design allows you to easily and quickly understand the essence of the problem, as well as clearly see all the important details and formulas necessary to solve it. In addition, the product page contains a detailed solution to the problem, which will help you understand it and apply your knowledge in practice.

Overall, this digital product is a great choice for anyone who wants to test their physics knowledge and enjoy a fun challenge!

Product description: This digital product is a fun physics challenge that tests your knowledge and skills in the field. It is a description of a problem in which a puck lies on the edge of a circular platform with radius R = 2.35 m, and the platform begins to rotate so that the path traveled by the puck increases in accordance with the equation s = Ct^2, where C = 0, 5 m/s^2. It is necessary to determine the moment in time when the washer begins to slide off the platform if the coefficient of friction is 0.2.

On the product page you will find a detailed solution to the problem that will help you understand it and apply your knowledge in practice. The solution begins by deriving the law of conservation of energy and rewriting the equation for Newton's second law of motion in a circle. Then the necessary substitutions are made and the equation is solved with respect to time t.

The product page also contains a brief record of the conditions, formulas and laws used in the solution, the output of the calculation formula and the answer, which makes it easy and quick to understand the essence of the problem and its solution.

The HTML design of the product is made in a beautiful and laconic style, which makes viewing the page as convenient and enjoyable as possible.

Overall, this digital product is a great choice for anyone who wants to test their physics knowledge and enjoy a fun challenge!

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The product is not listed in this description. A physics problem is described that I can solve.

So, we have a circular platform with radius R = 2.35 m, on the edge of which lies a washer. The platform rotates so that the path traveled by the puck increases in accordance with the equation s = Ct^2, where C = 0.5 m/s^2. We need to find the moment in time when the puck slides off the platform if the coefficient of friction is 0.2.

To solve the problem, we will use the laws of dynamics and the equation of motion. Since the puck is on the edge of the platform, it is only acted upon by gravity. The frictional force does not play a role, since it is directed along the platform and not in the radial direction. Thus, we can write the equation for Newton's second law for the radial component of the force:

ma = m(d^2s/dt^2) = F_r = m*(v^2)/R,

where m is the mass of the puck, a is the radial acceleration, v is the speed of the puck, R is the radius of the platform.

In our case, the radial acceleration can be written as a = d^2s/dt^2 = 2C. Thus, the equation becomes:

m2C = m(v^2)/R.

From here we can find the speed of the puck at the edge of the platform:

v = sqrt(2C*R).

In order for the puck not to slide off the platform, it is necessary that the friction force be greater than the force of gravity:

f_tr = mumg >= m*v^2/R,

where mu is the friction coefficient, g is the acceleration of free fall.

We substitute the known values ​​and solve the equation for time t:

t = sqrt(muR2/C*g).

Thus, the answer to the problem consists of a calculation formula and a numerical value of time:

t = sqrt(0.22.352/0.5*9.81) ≈ 1.46 s.

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