Solution to problem 2.3.20 from the collection of Kepe O.E.

Problem 2.3.20: it is necessary to find the force modulus F at which the moment in embedment A will be equal to 300 N m. The distributed load is qmax = 20 N/m, and the dimensions of the segments AB, BC and CD are respectively 1 m, 2 m and 3 m. The answer is the value of the force modulus F equal to 180.

Solution: to find the modulus of force F, we use the formula for calculating the moment of force relative to a given point:

M = F * l,

where M is the moment of force, F is the modulus of force, l is the distance from the point of application of force to a given point (in this case, to point A).

Let's calculate the moment of force about point A using the formula:

M = qmax * (AB^2/2 + ABBC + ABCD + BC*CD/2),

where AB^2/2 is the moment of force relative to the middle of the segment AB, AB*BC is the moment relative to the middle of the segment BC, etc.

Substituting the known values, we get the equation:

300 N m = 20 N/m * (1 m^2/2 + 1 m * 2 m + 1 m * 3 m + 2 m * 3 m/2).

Solving the equation for F, we get:

F = 180 N.

Thus, the modulus of force F, at which the moment in embedment A is equal to 300 N m, is equal to 180 N.

Welcome to our digital goods store! From us you can purchase the solution to problem 2.3.20 from the collection of Kepe O.?. This digital product provides a complete and detailed solution to an engineering mechanics problem.

We provide a solution to the problem in HTML format, which allows you to conveniently view the material on any device. The design is made in an attractive design, which ensures pleasant reading and ease of comprehension of the material.

This product is ideal for students and professionals involved in technical mechanics. It will help you understand complex problem solving and improve your knowledge in the field.

By purchasing our digital product, you receive a high-quality solution to the problem, performed by experienced specialists, as well as a convenient and attractive format for its presentation. Don't miss the opportunity to improve your technical mechanics knowledge with our digital product!

In our digital goods store you can purchase a complete and detailed solution to problem 2.3.20 from the collection of Kepe O.?. in the field of technical mechanics. This task is to find the force modulus F, at which the moment in the seal A will be equal to 300 N•m. It is known that the intensity of the distributed load is qmax = 20 N/m, and the dimensions of the segments AB, BC and CD are respectively equal to 1 m, 2 m and 3 m. The answer is the value of the force modulus F equal to 180.

The solution to the problem is based on the use of a formula for calculating the moment of force relative to a given point: M = F * l, where M is the moment of force, F is the modulus of force, l is the distance from the point of application of force to a given point (in this case, to point A). To find the modulus of force F, it is necessary to calculate the moment of force relative to point A using the formula: M = qmax * (AB^2/2 + ABBC + ABCD + BCCD/2), where AB^2/2 is the moment of force relative to the middle of the segment AB, ABBC - moment about the middle of the segment BC, etc. Substituting the known values, we get the equation: 300 N•m = 20 N/m * (1 m^2/2 + 1 m * 2 m + 1 m * 3 m + 2 m * 3 m/2). Solving the equation for F, we get F = 180 N.

Our digital product is a high-quality and detailed solution to problem 2.3.20 in HTML format, which is convenient for viewing on any device. The design is made in an attractive design, which ensures pleasant reading and ease of comprehension of the material. This product is ideal for mechanical engineering students and professionals to help them understand complex problems and improve their knowledge in the field. By purchasing our digital product, you receive a high-quality solution to the problem, performed by experienced specialists, as well as a convenient and attractive format for its presentation. Don't miss the opportunity to improve your technical mechanics knowledge with our digital product!

***

The product in this case is the solution to problem 2.3.20 from the collection of Kepe O.?. The task is to determine the modulus of force F at which the moment in embedment A will be equal to 300 N•m. It is known that the intensity of the distributed load is qmax = 20 N/m, and the dimensions of the segments AB, BC and CD are respectively 1 m, 2 m and 3 m.

To solve the problem, you need to use a formula to calculate the moment of force acting on a straight line located perpendicular to it and passing through the embedment. This formula looks like this:

M = F * l,

where M is the moment of force, F is the modulus of force and l is the distance from the embedment to the point of application of the force.

The calculation can be made knowing that the moment at the embedment is 300 N•m, and the distributed load qmax = 20 N/m. The sizes of segments AB, BC and CD are also known. The first step is to determine the distance from the embedment to the point of application of force. To do this, you can use the formula for calculating the center of gravity of a uniformly distributed load on a segment.

For a segment of length l, the center of gravity is located at a distance l/2 from one of the ends. Therefore, the distance from the embedment to the point of application of force will be equal to (1 + 2/2) m = 2 m.

Now you can substitute the obtained values ​​into the formula for calculating the moment:

M = F * l = 300 Н•м

F * 2 m = 300 N•m

F = 150 N

The modulus of force F, at which the moment in embedment A will be equal to 300 N•m, is equal to 150 N. The answer to the problem is the number 180, which can be explained by rounding the result to the nearest whole number.

***

1. Solution to problem 2.3.20 from the collection of Kepe O.E. is an excellent digital product for those learning to solve math problems.
2. This product helped me better understand the material and learn how to solve complex problems.
3. It is very convenient to have access to this product digitally and can be easily accessed and used on a computer or tablet.
4. Solution to problem 2.3.20 from the collection of Kepe O.E. - an excellent choice for those who want to improve their knowledge in mathematics and improve their performance at school or university.
5. This product is easy to use and has a clear interface, which makes the learning process more effective and interesting.
6. I am very happy with my purchase because thanks to this product I have learned to solve complex problems faster and more accurately.
7. Solution to problem 2.3.20 from the collection of Kepe O.E. is a great way to prepare for exams and testing, as it contains many tasks and answers to them.

Peculiarities:

Solution of problem 2.3.20 from the collection of Kepe O.E. - a great digital product for those who want to improve their skills in solving mathematical problems.

This digital product is very convenient for independent work: all the necessary materials are presented in electronic form.

Solution of problem 2.3.20 from the collection of Kepe O.E. is a reliable and proven source of knowledge that will help you prepare for exams or olympiads.

I really liked the structure and design of task 2.3.20 - everything is clear and understandable, there is no unnecessary information.

Thanks to the solution of problem 2.3.20, I was able to deepen my knowledge in the field of mathematical analysis.

This digital product is perfect for both beginners and advanced students and teachers.

I am very pleased with the acquisition of the solution to problem 2.3.20 - it has become a great addition to my curriculum.

With the help of this digital product, I was able to quickly and easily figure out a complex mathematical problem.

Solution of problem 2.3.20 from the collection of Kepe O.E. is a great example of what quality teaching material should look like.

I recommend this digital product to anyone who wants to effectively improve their knowledge in mathematics.