Some ammonia molecules have energy

A certain group of ammonia molecules has the energy of chaotic motion, which is twice the energy of the same number of nitrogen molecules. If the volume of ammonia is twice as large as the volume of nitrogen, then what is the ratio of the pressures of these gases? There are two approaches you can use for this task.

The first solution: Consider the Boyle-Marriott law, which states that at a constant temperature and amount of substance, pressure is inversely proportional to the volume of the gas. Accordingly, the pressure of ammonia and nitrogen should be inversely proportional to their volumes. Since the volume of ammonia is twice the volume of nitrogen, the pressure of nitrogen must be twice the pressure of ammonia.

Second solution method Consider the ideal gas formula: pV = nRT, where p is the gas pressure, V is its volume, n is the amount of gas substance, R is the universal gas constant, T is the gas temperature.

For ammonia and nitrogen, the amount of substance, the universal gas constant and the temperature are the same. It is also known from the problem conditions that the volume of ammonia is twice the volume of nitrogen. Substituting these values ​​into the ideal gas formula, we obtain: p(2V) = nRT for ammonia, pV = nRT for nitrogen.

Dividing the first equation by the second, we get: p(2V)/(pV) = 2, that is, the ammonia pressure is two times less than the nitrogen pressure.

Answer: Ammonia pressure is half that of nitrogen pressure.

Some ammonia molecules have energy

This digital product provides a detailed solution to a problem involving the energy of ammonia and nitrogen molecules. The product description presents two ways to solve the problem, as well as a brief record of the conditions, formulas and laws used in the solution. The solution to the problem is accompanied by a calculation formula and answer. If you have any questions about the solution, you can contact us and we will be happy to help you understand the problem.

Beautiful html design of the product makes it easy to navigate the task description and quickly find the information you need. You can purchase this digital product and get access to a detailed solution to the problem at any time convenient for you.

This product is a detailed solution to problem No. 20272, related to the energy of ammonia and nitrogen molecules. The problem states that the chaotic movement of a certain number of ammonia molecules has twice the energy of the same number of nitrogen molecules. In this case, the volume of ammonia is twice the volume of nitrogen.

The product description presents two ways to solve the problem. The first way is to use the Boyle-Marriott law, which states that at a constant temperature and amount of substance, pressure is inversely proportional to the volume of the gas. According to this law, the pressure of ammonia and nitrogen should be inversely proportional to their volumes.

The second solution is to use the ideal gas formula: pV = nRT, where p is the gas pressure, V is its volume, n is the amount of gas substance, R is the universal gas constant, T is the gas temperature. For ammonia and nitrogen, the amount of substance, the universal gas constant and the temperature are the same. By substituting known values ​​into the ideal gas formula, one can obtain the ratio of ammonia and nitrogen pressures.

The solution to the problem is accompanied by a calculation formula and answer. Designing a product in the form of a beautiful HTML document makes it easy to navigate the task description and quickly find the information you need. If you have any questions about solving a problem, you can contact us and we will be happy to help you figure it out. You can purchase this digital product and get access to a detailed solution to the problem at any time convenient for you.


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A certain number of ammonia molecules have energy in the form of chaotic movement, which is twice as much as that of the same number of nitrogen molecules.

Solution tasks 20272:

Problem condition: A certain number of ammonia molecules have twice the energy of chaotic motion as the same number of nitrogen molecules. What is the ratio of the pressures of these gases if ammonia occupies a volume twice as large as nitrogen? Suggest two solutions.

First way: From the conditions of the problem it follows that ammonia has twice the energy of movement than nitrogen. This means that under the same conditions (temperature and pressure), ammonia molecules will move faster than nitrogen molecules. Therefore, the ammonia pressure must be greater than the nitrogen pressure.

According to the conditions of the problem, the volume of ammonia is twice as large as the volume of nitrogen, that is, V(NH3) = 2V(N2). Let the nitrogen pressure be P(N2), then the ammonia pressure will be P(NH3).

To solve the problem, we use the Boyle-Marriott law: pV = const.

For nitrogen: P(N2)*V(N2) = const. For ammonia: P(NH3)*V(NH3) = const.

Substitute V(NH3) = 2V(N2) into the second equation: Р(NH3)*2V(N2) = const.

Divide the equation for ammonia by the equation for nitrogen: Р(NH3)/Р(N2) = (V(N2)/V(NH3))*2 = 1/2

Thus, the pressure ratio of ammonia and nitrogen is 1:2.

Second way: Let's use the formula for the average kinetic energy of molecules:

E = (3/2)kT

where E is the average kinetic energy of molecules, k is Boltzmann's constant, T is the temperature in Kelvin.

At the same temperature, the average kinetic energy of ammonia molecules will be twice that of nitrogen molecules:

(3/2)kT(NH3) = 2*(3/2)kT(N2)

Considering that the volume of ammonia is twice as large as the volume of nitrogen, then the number of ammonia molecules is twice as large as the number of nitrogen molecules:

n(NH3) = 2*n(N2)

Therefore, the ammonia pressure must be twice the nitrogen pressure:

P(NH3) = 2*P(N2)

Thus, the pressure ratio of ammonia and nitrogen is 1:2.


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