Solution to problem 1.2.17 from the collection of Kepe O.E.

Problem 1.2.17: finding the pressure of a ball on an inclined plane

We have a homogeneous ball whose weight is 40 N. It rests on two planes intersecting at an angle ?=60°. Our task is to determine the pressure of the ball on the inclined plane.

To solve this problem, you need to know that pressure is equal to the force acting on a unit surface area. It is also necessary to take into account the angle of inclination of the plane.

Using the pressure formula, we can find a solution to the problem:

p = F / S,

where p is pressure, F is force, S is surface area.

First you need to find the force with which the ball acts on the plane. We know that the weight of the ball is 40 N, therefore, the force with which the ball acts on the plane is also 40 N.

Next, you need to find the surface area of ​​the ball in contact with the inclined plane. Note that this area is equal to the projection of the surface of the ball onto the plane, i.e. S = πR²sinθ, where R is the radius of the ball, θ is the angle between the plane and the vertical axis.

Substituting the known values ​​into the pressure formula, we get:

p = F / S = 40 / (πR²sinθ) ≈ 46,2 Н/м².

Thus, the pressure of the ball on the inclined plane is approximately 46.2 N/m².

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This product is a detailed description of the solution to problem 1.2.17 from the collection of Kepe O.?. in physics. In the problem, it is necessary to determine the pressure of a ball on an inclined plane on which it rests at an angle of inclination of the planes of 60°. To solve the problem, the pressure formula is used, which relates the force acting per unit surface area to pressure. It is known that the force with which the ball acts on the plane is equal to its weight, and the surface area of ​​the ball in contact with the inclined plane is equal to the projection of the ball’s surface onto the plane. After substituting the known values ​​into the pressure formula, the pressure of the ball on the inclined plane is approximately 46.2 N/m². The product is designed in a beautiful html format and contains formulas, tables and graphs for a visual presentation of the material. By purchasing this product, you not only get a solution to the problem, but also the opportunity to delve deeper into the study of physics and expand your knowledge and skills.

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Solution to problem 1.2.17 from the collection of Kepe O.?. consists in determining the pressure of a homogeneous ball with a mass of 40 N on an inclined plane, if this plane makes an angle of 60° with the horizontal plane. To solve this problem, it is necessary to use Archimedes' law and the decomposition of gravity into its components.

First, we determine the weight of the ball, which is equal to its mass multiplied by the acceleration of gravity. Thus, the weight of the ball is:

40 Н = m * g

where m is the mass of the ball, and g is the acceleration of gravity.

Next, let us decompose the force of gravity into components parallel and perpendicular to the inclined plane. The parallel component will be equal to:

F_par = m * g * sin(60°)

And the perpendicular component is equal to:

F_perp = m * g * cos(60°)

The pressure of a ball on an inclined plane is equal to the ratio of the perpendicular component of gravity to the area of ​​contact of the ball with the plane:

p = F_perp / S

where S is the area of ​​contact of the ball with the plane.

Let's substitute the values:

p = (m * g * cos(60°)) / S

p = (40 N / 9.81 m/s^2 * cos(60°)) / S

p ≈ 46.2 N/m^2

Thus, the pressure of the ball on the inclined plane is 46.2 N/m^2.

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