Solution K1-74 (Figure K1.7 condition 4 S.M. Targ 1989)

In problem K1-74 (Figure K1.7 condition 4 S.M. Targ 1989) there are two parts - K1a and K1b, which need to be solved.

K1a: Point B moves in the xy plane (Fig. K1.0 - K 1.9, Table K1). The trajectory of a point in the figures is shown conventionally. The equations of motion of a point are given as x = f1(t), y = f2(t), where x and y are expressed in centimeters and t in seconds. It is necessary to find the equation of the point's trajectory. For the moment of time t1 = 1 s, it is necessary to determine the speed and acceleration of the point, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. x = f1(t) is indicated in the figures, and y = f2(t) is given in the table. K1 (for Fig. 0-2 in column 2, for Fig. 3-6 in column 3, for Fig. 7-9 in column 4). As in tasks C1 - C4, the figure number is selected according to the penultimate digit of the code, and the condition number in the table. K1 - according to the last one.

K1b: The point moves along a circular arc of radius R = 2 m according to the law s = f(t), given in the table. K1 in column 5 (s - in meters, t - in seconds), where s = AM is the distance of a point from some beginning A, measured along the arc of a circle. It is necessary to determine the speed and acceleration of the point at time t1 = 1 s. In the figure you need to depict vectors v and a, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

This product is a digital product, it is a solution to problem K1-74 (Figure K1.7 condition 4 S.M. Targ 1989) with a detailed description of the source data, solution methods and answers. The solution includes two parts - K1a and K1b, and is designed in accordance with beautiful html markup.

In problem K1a, it is necessary to find the equation of the trajectory of a point moving in the xy plane and determine the speed, acceleration, tangential and normal acceleration, and the radius of curvature at the corresponding point on the trajectory. The dependence x = f1(t) is indicated in the figures, and the dependence y = f2(t) is given in the table. K1.

In problem K1b, it is necessary to determine the speed and acceleration of a point moving along a circular arc of radius R = 2 m at time t1 = 1 s. In the figure, it is necessary to depict vectors v and a, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

This product is an ideal solution for those who are looking for a high-quality and accurate solution to problem K1-74 (Figure K1.7 condition 4 S.M. Targ 1989) with a beautiful design and convenient presentation of the material.

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Solution K1-74 is a set of problems consisting of two parts: K1a and K1b.

In problem K1a, it is necessary to find the equation for the trajectory of point B moving in the xy plane according to the given law of motion x = f1(t), y = f2(t). For the moment of time t1 = 1 s, it is necessary to determine the speed, acceleration, tangential and normal acceleration of the point, as well as the radius of curvature at the corresponding point of the trajectory. The dependence y = f2(t) is given in table. K1, and the dependence x = f1(t) is indicated in the figures. The figure number is selected according to the penultimate digit of the code, and the condition number in the table. K1 – according to the last one.

In problem K1b, a point moves along a circular arc of radius R = 2 m according to the law s = f(t), given in table. K1 in column 5 (s is the distance of a point from some origin A, measured along the arc of a circle). It is necessary to determine the speed and acceleration of the point at time t1 = 1 s. It is also required to depict vectors v and a in the figure, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

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