A long wire forms a circular loop tangent to

Given a wire that forms a circular loop tangent to the wire. The current flowing through the wire is 5 A. It is required to find the radius of the loop if it is known that the magnetic field strength at the center of the loop is 41 A/m.

Solution tasks 31115:

From the problem conditions it is known that the magnetic field strength at the center of the loop is 41 A/m. It is necessary to find the radius of the loop using the formula for calculating the magnetic field on the axis of a circular wire:

$$B = \frac{\mu_0}{4\pi} \cdot \frac{2I}{R}$$

Where:

  • B is the magnetic field strength on the axis of the circular wire;
  • I is the current strength flowing through the wire;
  • R is the radius of the circular loop;
  • $\mu_0$ is the magnetic constant equal to $4\pi \cdot 10^{ -7}$ H/m.

Substituting the values ​​into the formula, we get:

$$41 = \frac{4\pi \cdot 10^{ -7}}{4\pi} \cdot \frac{2 \cdot 5}{R}$$

Solving the equation for R, we get:

$$R = \frac{4\pi \cdot 10^{ -7} \cdot 2 \cdot 5}{41} \approx 1.54 \cdot 10^{ -5} \ м \approx 15.4 \ мм$$

Answer: The loop radius is approximately 15.4 mm.

If you have any questions regarding the solution, please write. We'll try to help.

Description of the digital product

Our digital goods store is pleased to introduce you to a new product - "A long wire forms a circular loop tangent to."

This digital product is a detailed solution to a physics problem involving electrical circuits. The problem considers a wire forming a circular loop tangent to the wire carrying a current of 5 A. It is necessary to find the radius of the loop if it is known that the magnetic field strength at the center of the loop is 41 A/m.

The product contains:

  • A detailed solution to the problem with a brief record of the conditions, formulas and laws used in the solution;
  • Derivation of the calculation formula;
  • Answer to the problem;
  • Beautiful design in HTML format.

Our digital product “A long wire forms a circular loop tangent to” will help you quickly and easily understand solving problems in physics and get an excellent grade in an exam or test.

This digital product is a detailed solution to a physics problem involving electrical circuits. The problem considers a wire forming a circular loop tangent to the wire carrying a current of 5 A. It is necessary to find the radius of the loop if it is known that the magnetic field strength at the center of the loop is 41 A/m.

The product contains:

  • a detailed solution to the problem with a brief record of the conditions, formulas and laws used in the solution;
  • derivation of the calculation formula;
  • answer to the problem;
  • beautiful design in HTML format.

Our digital product “A long wire forms a circular loop tangent to” will help you quickly and easily understand solving problems in physics and get an excellent grade in an exam or test.


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The product description is not related to the task provided. If you want to get a solution to the problem, I can help you with it.

To solve the problem, you need to use the formula to calculate the magnetic field at the center of a circular loop:

B = (μ₀ * I) / (2 * R)

where B is the magnetic induction at the center of the loop, μ₀ is the magnetic constant (4π * 10^-7 T/m), I is the current strength in the wire and R is the radius of the loop.

From the conditions of the problem it is known that B = 41 A/m and I = 5 A. Substituting these values ​​into the formula, we obtain:

41 = (4π * 10^-7 * 5) / (2 * R)

Simplifying the expression, we get:

R = (4π * 10^-7 * 5) / (2 * 41) ≈ 7.07 mm

Thus, the loop radius is about 7.07 mm.


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