Given a wire that forms a circular loop tangent to the wire. The current flowing through the wire is 5 A. It is required to find the radius of the loop if it is known that the magnetic field strength at the center of the loop is 41 A/m.
Solution tasks 31115:
From the problem conditions it is known that the magnetic field strength at the center of the loop is 41 A/m. It is necessary to find the radius of the loop using the formula for calculating the magnetic field on the axis of a circular wire:
$$B = \frac{\mu_0}{4\pi} \cdot \frac{2I}{R}$$
Where:
Substituting the values into the formula, we get:
$$41 = \frac{4\pi \cdot 10^{ -7}}{4\pi} \cdot \frac{2 \cdot 5}{R}$$
Solving the equation for R, we get:
$$R = \frac{4\pi \cdot 10^{ -7} \cdot 2 \cdot 5}{41} \approx 1.54 \cdot 10^{ -5} \ м \approx 15.4 \ мм$$
Answer: The loop radius is approximately 15.4 mm.
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This digital product is a detailed solution to a physics problem involving electrical circuits. The problem considers a wire forming a circular loop tangent to the wire carrying a current of 5 A. It is necessary to find the radius of the loop if it is known that the magnetic field strength at the center of the loop is 41 A/m.
The product contains:
Our digital product “A long wire forms a circular loop tangent to” will help you quickly and easily understand solving problems in physics and get an excellent grade in an exam or test.
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To solve the problem, you need to use the formula to calculate the magnetic field at the center of a circular loop:
B = (μ₀ * I) / (2 * R)
where B is the magnetic induction at the center of the loop, μ₀ is the magnetic constant (4π * 10^-7 T/m), I is the current strength in the wire and R is the radius of the loop.
From the conditions of the problem it is known that B = 41 A/m and I = 5 A. Substituting these values into the formula, we obtain:
41 = (4π * 10^-7 * 5) / (2 * R)
Simplifying the expression, we get:
R = (4π * 10^-7 * 5) / (2 * 41) ≈ 7.07 mm
Thus, the loop radius is about 7.07 mm.
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