Solution K1-93 (Figure K1.9 condition 3 S.M. Targ 1989)

Solution of problem K1-93, condition 3 S.M. Targ 1989, includes two parts - K1a and K1b.

The following conditions are imposed on problem K1a: point B moves in the xy plane, and its trajectory is shown conventionally in Figures K1.0-K1.9 (Table K1). The law of motion of a point is given by the equations x=f1(t), y=f2(t), where x and y are expressed in centimeters, and t in seconds. It is required to find the equation of the point's trajectory, determine the speed and acceleration of the point at the time t1 = 1 s, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x=f1(t) is indicated in the figures, and the dependence y=f2(t) is shown in the table. K1 (for Fig. 0-2 in column 2, for Fig. 3-6 in column 3, for Fig. 7-9 in column 4). When choosing a figure number, you must use the penultimate digit of the code, and the condition number in the table. K1 - the last one.

The following conditions are imposed on problem K1b: the point moves along a circular arc of radius R=2 m according to the law s=f(t), given in table. K1 in column 5 (s - in meters, t - in seconds), where s=AM is the distance of the point from the beginning of A, measured along the arc of a circle. It is required to determine the speed and acceleration of the point at the time t1=1 s and depict the vectors v and a in the figure, assuming that the point is in position M at this moment, and the positive direction of reference s is from A to M.

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The product is designed in HTML format, which allows you to conveniently and quickly view information both on a computer and on mobile devices. Two parts of the problem are described - K1a and K1b, each of which contains a detailed solution to the problem and answers to all the questions posed.

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“Solution K1-93 (Figure K1.9 condition 3 by S.M. Targ 1989)” is a digital product that is a solution to problem K1-93, condition 3 from the book by S.M. Targa, published in 1989. The solution includes two parts - K1a and K1b.

In problem K1a, it is necessary to determine the equation for the trajectory of point B moving in the xy plane according to a given law of motion. It is also required to find the speed and acceleration of the point at time t1 = 1 s, as well as the tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x=f1(t) is indicated in the figures, and the dependence y=f2(t) is shown in the table. K1.

In problem K1b it is necessary to determine the speed and acceleration of a point moving along a circular arc of radius R=2 m according to the given law s=f(t), given in table. K1 in column 5 (s - in meters, t - in seconds). It is also required to depict vectors v and a in the figure, assuming that the point is in position M at time t1 = 1 s, and the positive direction of reference s is from A to M.

The product is designed in HTML format, which allows you to conveniently and quickly view information both on a computer and on mobile devices. The solution is beautifully designed, which makes it convenient and practical for use by both professionals in the field of mathematics and physics, as well as students. By purchasing this digital product, you get a unique opportunity to quickly and easily study the solution to problem K1-93, condition 3 S.M. Targa, which can be useful when preparing for exams or in scientific activities.

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Solution K1-93 is a problem that consists of two parts: K1a and K1b. In problem K1a, it is necessary to find the equation for the trajectory of a point moving in the xy plane using the given equations of motion x = f1(t) and y = f2(t), where x and y are expressed in centimeters, and t in seconds. You also need to determine the speed and acceleration of the point at time t1 = 1 s, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point on the trajectory.

Problem K1b is that a point moves along an arc of a circle of radius R = 2 m according to the law s = f(t), given in table K1 in column 5 (s - in meters, t - in seconds), where s = AM - the distance of a point from some origin A, measured along an arc of a circle. It is necessary to determine the speed and acceleration of the point at time t1 = 1 s. You also need to depict vectors v and a in the figure, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

To solve the problem, you must use the data provided: equations of motion and table K1. You also need to know how to determine speed, acceleration, tangential and normal acceleration, as well as the radius of curvature at a given point on the trajectory.

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