A small body of mass m moves in the XY plane along

A small body of mass m moves in the XY plane along the x axis with a constant speed V. What is the angular momentum of the body relative to the point (0.2)? Indicate on the drawing the direction of the angular momentum. Problem 10643. Detailed solution with a brief record of the conditions, formulas and laws used in the solution, derivation of the calculation formula and answer. If you have any questions regarding the solution, please write. I try to help.

Consider a body of mass m moving in the XY plane along the x axis with speed V. The angular momentum of the body relative to the point (0,2) can be calculated using the formula L = r x p, where r is the radius vector of the point relative to the center of the coordinate system, p is the vector body impulse.

Since the body moves along the x-axis, its momentum can be written as p = mV e_x, where e_x is the unit vector along the x-axis.

The radius vector of the point (0,2) relative to the center of the coordinate system can be written as r = -2 e_y, where e_y is the unit vector along the y axis.

Thus, the angular momentum of the body relative to the point (0,2) is equal to:

L = r x p = (-2 e_y) x (mV e_x) = -2mVe_z,

where e_z is a unit vector perpendicular to the XY plane and directed upward.

Thus, the angular momentum of the body relative to the point (0,2) is equal to -2mV unit of angular momentum and is directed upward relative to the XY plane.

A small body of mass m moves in the XY plane along the x axis

This digital product contains a detailed solution to Problem 10643, which is a classic problem involving the motion of a body in the XY plane. The solution includes a brief recording of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer.

You can easily understand how to solve such problems and apply the laws of mechanics to solve various physics problems.

This digital product is very useful for students, school students, students and anyone interested in physics and mechanics.

Product description:

This digital product contains a detailed solution to Problem 10643, which is a classic problem involving the motion of a body in the XY plane. The solution uses the laws of mechanics and formulas that allow one to calculate the angular momentum of a body relative to the point (0,2), provided that a small body of mass m moves in the XY plane along the x axis with a constant speed V.

Solving a problem includes a brief recording of the conditions, formulas and laws used in the solution, derivation of the calculation formula and the answer. In this case, the drawing indicates the direction of the angular momentum, which turns out to be directed upward relative to the XY plane.

This digital product will be useful for students at school or university, as well as for anyone who is interested in physics and mechanics and wants to deepen their knowledge in this area. Solving the problem will help you understand how to apply the laws of mechanics to solve various problems in physics.

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This product is a description of a physics problem, namely the calculation of the angular momentum of a small body of mass m moving in the XY plane along the x axis with a constant speed V, relative to the point (0,2).

Momentum is a vector quantity that determines the ability of a body to rotate around an axis. To calculate the angular momentum of the body relative to the point (0,2), it is necessary to multiply the radius vector from the point to the center of mass of the body by the vector of the body's momentum.

The formula for calculating the angular momentum L is as follows: L = r x p, where r is the radius vector from the point to the center of mass of the body, p is the momentum vector.

In this case, since the body moves along the x axis, the radius vector r will have coordinates (0, -2, 0). The momentum vector p will have coordinates (mV, 0, 0), since the body moves along the x axis with a constant speed V.

Substituting the values ​​into the formula, we get: L = (0, -2, 0) x (mV, 0, 0) = (0, 0, -2mV)

Thus, the angular momentum of the body relative to the point (0,2) is equal to the vector (0, 0, -2mV). The direction of the angular momentum can be determined by the gimlet rule: if the direction of the vector r relative to the circle in which the body is moving coincides with the direction of the momentum vector, then the direction of the angular momentum will be along the z axis, directed towards the observer. In this case, since the body is moving in the positive direction of the x-axis, and the radius vector is directed downward, the direction of the angular momentum will be along the z-axis, directed away from the observer.

For clarity, you can draw a drawing that shows the direction of the vectors r, p and L.

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