Solution to problem 15.4.3 from the collection of Kepe O.E.

15.4.3 At the initial moment of time, a homogeneous disk with mass m = 30 kg and radius R = 1 m is at rest. Then it begins to rotate uniformly with constant angular acceleration? = 2 rad/s2. Let's find the kinetic energy of the disk at the time t = 2 s after the start of motion.

We use the formula for the kinetic energy of a solid body: K = (1/2) * I * w^2, where I is the moment of inertia of the body, w is the angular velocity of the body.

The moment of inertia of a homogeneous disk relative to its center is equal to I = (1/2) * m * R^2. The angular velocity of the disk after time t is calculated by the formula: w = ? *t.

Thus, the kinetic energy of the disk at time t = 2 s will be equal to: K = (1/2) * I * w^2 = (1/2) * (1/2) * m * R^2 * (? * t)^2 = 120 J.

So, the kinetic energy of the disk at time t = 2 s after the start of motion is equal to 120 J.

Solution to problem 15.4.3 from the collection of Kepe O.?.

We present to your attention the solution to problem 15.4.3 from the collection of Kepe O.?. This digital product is a great help for those who are preparing for exams or simply want to deepen their knowledge in physics.

In this solution you will find a detailed algorithm for solving the problem, as well as an answer with step-by-step calculations. Our team of professional physicists and methodologists has thoroughly tested the solution so that you can be confident that it is correct.

This digital product is easy to download and use on any device. You will receive a PDF file that you can open on your computer, tablet or smartphone.

Don't waste time searching for solutions to problems on the Internet. With our digital product you will receive a reliable and accurate solution to problem 15.4.3 from the collection of Kepe O.?. in a convenient format.

99 rub.

Digital product "Solution to problem 15.4.3 from the collection of Kepe O.?." represents a detailed solution to a physical problem. In this case, we are talking about a problem that describes the motion of a homogeneous disk with a mass of 30 kg and a radius of 1 m, which begins to rotate uniformly with an angular acceleration of 2 rad/s². The question is what is the kinetic energy of the disk 2 seconds after it starts moving.

The solution to the problem is based on the use of the formula for the kinetic energy of a solid body: K = (1/2) * I * w^2, where K is the kinetic energy, I is the moment of inertia of the body, w is the angular velocity of the body. The moment of inertia of a homogeneous disk relative to its center is equal to I = (1/2) * m * R^2, where m is the mass of the disk, R is the radius of the disk. The angular velocity of the disk after time t is calculated by the formula: w = ? * t, where? - angular acceleration of the disk.

Therefore, to solve the problem, it is necessary to calculate the moment of inertia of the disk, the angular velocity of the disk after 2 seconds of movement, and then substitute the obtained values ​​into the formula for kinetic energy. The result of the solution is the value of the kinetic energy of the disk at the time t = 2 s after the start of movement, which is equal to 120 J.

Digital product "Solution to problem 15.4.3 from the collection of Kepe O.?." is a useful resource for those interested in physics or preparing for exams. It contains a detailed description of the algorithm for solving the problem, as well as an answer with step-by-step calculations, verified by a team of professional physicists and methodologists. The PDF file is easy to download and accessible on any device, making it a convenient and reliable resource for problem solving. The price of the product is 99 rubles.

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Solution to problem 15.4.3 from the collection of Kepe O.?. consists in determining the kinetic energy of a homogeneous disk with a mass of 30 kg and a radius of 1 m, which begins to rotate from a state of rest uniformly accelerated with a constant angular acceleration ? = 2 rad/s2. It is necessary to determine the kinetic energy of the disk at the time t = 2 s after the start of motion.

To solve the problem, you need to use the formula for the kinetic energy of a rotating body:

K = (1/2) * I * w^2,

where K is the kinetic energy of the body, I is the moment of inertia of the body, w is the angular velocity of the body.

The moment of inertia of a homogeneous disk is equal to I = (1/2) * m * R^2, where m is the mass of the disk, R is the radius of the disk.

The angular velocity of the disk can be determined by the formula w = ? * t, where? - angular acceleration of the disk, t - time of motion of the disk.

Thus, substituting known values ​​into the formulas, we get:

I = (1/2) * 30 kg * (1 m)^2 = 15 kg * m^2 w = 2 rad/s^2 * 2 s = 4 rad/s K = (1/2) * 15 kg * m^2 * (4 rad/s)^2 = 120 J

So, the kinetic energy of the disk at time t = 2 s after the start of motion is equal to 120 J.

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