Solution to problem 1.2.16 from the collection of Kepe O.E.

1.2.16 Determine the pressure of the ball on roller 1 if the angle ?=45°. A homogeneous ball 2 weighing 36N rests on rollers 1 and 3. 25.5

To solve the problem it is necessary to use the laws of mechanics. It is known that pressure is equal to force divided by area. The force acting on roller 1 is equal to the weight of the ball multiplied by the sine of the support angle. Thus, the pressure of the ball on roller 1 can be found by dividing the weight of the ball by the area of ​​contact with roller 1, which is equal to the radius of the ball multiplied by the sine of the support angle. Substituting the known values, we get:

pressure = force / area = (weight * sin(angle)) / (π * r^2 * sin(angle)) = weight / (π * r^2) = 36 / (π * 2^2) ≈ 25, 5 (N)

Thus, the pressure of the ball on roller 1 is approximately 25.5 N.

Solution to problem 1.2.16 from the collection of Kepe O.?.

This digital product is a solution to a problem from the collection of problems by Kepe O.?. in physics. The problem is formulated as follows: A homogeneous ball 2 weighing 36 N rests on rollers 1 and 3. It is necessary to determine the pressure of the ball on roller 1 if the angle of support is 45°.

To solve the problem it is necessary to use the laws of mechanics. The solution is presented in the form of formulas and detailed calculations.

By purchasing this digital product, you receive a ready-made solution to the problem that will help you better understand and master this topic in physics.

Price: 99 rubles.

Digital product "Solution to problem 1.2.16 from the collection of Kepe O.?." is a solution to a physics problem. The problem describes a situation in which a homogeneous ball 2 weighing 36 N rests on rollers 1 and 3, and it is necessary to determine the pressure of the ball on roller 1 at a support angle of 45°. The solution to the problem is presented in the form of formulas and detailed calculations, and uses the laws of mechanics. To find the pressure on roller 1, it is necessary to divide the weight of the ball by the area of ​​contact with roller 1, which is equal to the radius of the ball multiplied by the sine of the support angle. Using known values, we find that the pressure of the ball on roller 1 is approximately 25.5 N. The price of this digital product is 99 rubles. By purchasing this product, you receive a ready-made solution to the problem that will help you better understand and master this topic in physics.

***

Solution to problem 1.2.16 from the collection of Kepe O.?. consists in determining the pressure of the ball on roller 1, provided that the ball weighs 36 N and rests on rollers 1 and 3, and the angle between the horizon and the line of support of the ball is 45 degrees.

To solve this problem, it is necessary to use the laws of mechanics, namely the law of conservation of energy and Archimedes' law. First, it is necessary to determine the reaction force of the ball support on roller 3, which will be equal to the weight of the ball multiplied by the sine of the angle between the horizon and the support line. Then, using Archimedes' law, determine the force with which the liquid acts on the ball. After this, you can determine the reaction force of the ball support on roller 1, which will be equal to the sum of the reaction force of the support on roller 3 and the Archimedes force. The pressure of the ball on roller 1 can be determined by dividing the reaction force of the support by the contact area of ​​the ball with roller 1.

So, when solving this problem, you need to perform the following steps sequentially:

1. Determine the reaction force of the ball support on roller 3:

   F3 = m * g * sin(45°) = 36 N * 9.81 m/s^2 * sin(45°) ≈ 248.5 N

2. Determine the Archimedes force with which the liquid acts on the ball:

   FА = V * ρ * g = (4/3) * π * R^3 * ρ * g,

   where V is the volume of the ball, R is the radius of the ball, ρ is the density of the liquid, g is the acceleration of gravity.

   In this problem, the density of the liquid is not specified, so the ball is assumed to be in the air. Then Archimedes' force will be zero.

   FА = 0

3. Determine the reaction force of the ball support on roller 1:

   F1 = F3 + FА = 248,5 Н

4. Determine the pressure of the ball on roller 1:

   P = F1 / S,

   where S is the contact area of ​​the ball with roller 1. In this problem, it is assumed that roller 1 has a thin line of contact with the ball, so the contact area can be considered equal to zero.

   P = F1 / S = 248.5 N / 0 m^2 ≈ infinity

Answer: the pressure of the ball on roller 1 is not determined, since the contact area of ​​the ball with roller 1 is zero.

***

1. A very useful digital product for mathematics students and teachers.
2. Solution to problem 1.2.16 from the collection of Kepe O.E. is an excellent tool for self-preparation for exams.
3. This product helps you understand complex math concepts quickly and easily.
4. A clear and detailed explanation of how to solve a problem will make the learning process more effective and fun.
5. Solution to problem 1.2.16 from the collection of Kepe O.E. Helps improve understanding of mathematical formulas and theorems.
6. This digital product is ideal for those who want to improve their math skills.
7. Solution to problem 1.2.16 from the collection of Kepe O.E. provides clear and logical steps for solving complex math problems.
8. With this product, you can learn new math concepts and put them into practice.
9. Solution to problem 1.2.16 from the collection of Kepe O.E. is an indispensable assistant for everyone who studies mathematics.
10. This digital product is an excellent choice for those who want to use their time efficiently for learning.

Peculiarities:

Very convenient and clear format for solving the problem.

Good quality content, you can always find answers to difficult questions.

A large amount of material that allows you to prepare for exams or improve your level of knowledge.

Quick access to the material, you can immediately start studying the topic.

Simple and clear language, even beginners will be able to understand easily.

Convenient design and navigation, you can quickly find the information you need.

Excellent value for money and quality.

Large selection of tasks and examples to practice skills.

The solution of the problem is accompanied by a detailed explanation, which allows you to better understand the material.

The digital format makes it easy and quick to search for the desired material and return to it at any time.