The volume of a sound with a frequency of 1 kHz decreased by 30 von

What is the intensity of a sound with a frequency of 1 kHz after passing through a thin plywood partition if its level decreased by 30 phons? Initially, the sound intensity was 10^-8 W/m^2.

Solution: The sound level, measured in phons, is related to the ratio of sound intensity before and after passing through the partition. The sound level decreased by 30 phons, which corresponds to a decrease in sound intensity by 10^(30/10) = 10^3 times. Therefore, the sound intensity after passing through the partition is:

10^-8 W/m^2 ÷ 10^3 = 10^-11 W/m^2

Thus, the sound intensity became equal to 10^-11 W/m^2 after passing through the plywood partition.

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This text describes a product that allows you to calculate the change in sound intensity when passing through a thin plywood partition. The problem mentions that the volume of a 1 kHz sound has decreased by 30 phons. This means that the sound level has decreased by a factor of 10^(30/10) = 10^3. Initially, the sound intensity was 10^-8 W/m^2. Therefore, the sound intensity after passing through the partition is 10^-8 W/m^2 ÷ 10^3 = 10^-11 W/m^2.

Thus, the answer to the problem is that the sound intensity became equal to 10^-11 W/m^2 after passing through the plywood partition.

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The product description refers to sound-absorbing materials that are used to reduce noise levels in a room. In this case, the volume of a 1 kHz sound decreased by 30 phon when passing through a thin plywood partition. This means that the sound intensity has decreased by a factor of 10^3, since 30 von is an equivalent decrease in sound intensity by a factor of 10^3.

Therefore, the sound intensity after passing through the partition will be:

I = (10^-8 W/m^2) / 10^3 = 10^-11 W/m^2.

To solve the problem, the Lambert-Booger law was used, which states that the intensity of sound decreases exponentially as it passes through a medium. The formula for calculating the intensity of sound through a medium is as follows:

I = I0 * e^(-αd),

where I0 is the initial sound intensity, α is the attenuation coefficient, d is the thickness of the medium.

In this case, the thickness of the medium is equal to the thickness of the plywood partition, and the attenuation coefficient is determined by the material of the partition and the sound frequency. However, in this problem the attenuation coefficient is unknown, so we use the background - a dimensionless unit that is equivalent to a decrease in sound intensity of 10 logarithmic units.

Thus, the intensity of sound decreases by 10^((αd)/10) times when passing through a medium of thickness d with attenuation coefficient α. In this case, the decrease in sound intensity is 10^3 times, which corresponds to 30 von.

From this we can find the attenuation coefficient α:

10^((αd)/10) = 10^3

(αd)/10 = 3

αd = 30

This means that αd is equal to 30 von, and the thickness of the partition d is unknown. However, to solve the problem we do not need to know the specific thickness of the partition, so we can simply express the attenuation coefficient α:

α = 30/d

Thus, the sound intensity after passing through the partition will be equal to I = I0 * e^(-αd) = I0 * e^(-30) = 10^-11 W/m^2.

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