Solution to problem 7.7.14 from the collection of Kepe O.E.

7.7.14 The aircraft follows a circular trajectory with a radius of r = 10 km. It is necessary to determine the speed of the aircraft in km/h if its normal acceleration is an = 6.25 m/s². (Answer: 900)

To solve this problem, it is necessary to use the formula for determining centripetal acceleration:

and = v^2 / r,

where ac is the centripetal acceleration, v is the speed, r is the radius of the trajectory.

It is also known that normal acceleration is expressed by the following formula:

an = v^2 / r,

where an is the normal acceleration.

Based on the conditions of the problem, we can express the speed of the aircraft:

v = √(an * r)

Substituting known values, we get:

v = √(6.25 m/s² * 10 km) ≈ 250 m/s ≈ 900 km/h

Thus, the speed of the aircraft is about 900 km/h.

Solution to problem 7.7.14 from the collection of Kepe O.?.

We present to your attention the solution to problem 7.7.14 from the collection of Kepe O.?. - a textbook that will help you successfully master the physics course and prepare for exams.

Problem 7.7.14 is a problem from the section “Dynamics of a material point”, which considers the movement of objects along a circular path. Along with this problem you will receive a detailed explanation of the theoretical material needed to solve it.

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Problem 7.7.14 from the collection of Kepe O.?. considers the movement of an aircraft along a circular trajectory with a radius r = 10 km and a known normal acceleration an = 6.25 m/s². It is necessary to determine the speed of the aircraft in km/h.

To solve this problem, you can use the formula for centripetal acceleration: ac = v^2 / r, where ac is centripetal acceleration, v is speed, r is the radius of the trajectory. It is also known that normal acceleration is expressed by the following formula: an = v^2 / r, where an is normal acceleration.

From the conditions of the problem we can express the speed of the aircraft: v = √(an * r). Substituting known values, we get:

v = √(6.25 m/s² * 10 km) ≈ 250 m/s ≈ 900 km/h.

Thus, the speed of the aircraft is about 900 km/h.

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Solution to problem 7.7.14 from the collection of Kepe O.?. consists in determining the speed of the aircraft in km/h for a given normal acceleration an and the radius of the circular trajectory r.

To solve this problem, it is necessary to use the formula for calculating the centripetal acceleration ac:

ac = v²/r,

where v is the speed of the aircraft, r is the radius of the circular trajectory.

It is also known that the normal acceleration an is related to the centripetal acceleration ac as follows:

ap = ac = v²/r.

From these two equations we can express the speed of the aircraft:

v = √(ап * r)

Substituting known values, we get:

v = √(6.25 m/s² * 10 km * 1000 m/km) ≈ 900 km/h

Thus, the speed of the plane in km/h is 900.

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