Solution to problem 2.6.6 from the collection of Kepe O.E.

2.6.6 It is necessary to find the largest weight of load 2, which must be placed on a homogeneous roller 1 with a mass of 5 kN, so that the roller begins to move to the left. To do this, a pair of forces with a moment M = 210 N • m is applied to the roller. The radius of the roller is R = 0.453 m, and the rolling friction coefficient is ? = 0.003 m. Answer: 428.

Solution to problem 2.6.6 from the collection of Kepe O.?.

We present to your attention the solution to problem 2.6.6 from the collection of Kepe O.?. - a valuable teaching aid for students of technical specialties.

This digital product is a solution to the problem of determining the largest weight of load 2 that must be placed on a homogeneous roller 1 of mass 5 kN in order for the roller to start moving to the left. The solution to this problem involves detailed analysis and calculations taking into account all known parameters, such as the rolling friction coefficient and the radius of the roller.

By purchasing this digital product, you receive a complete and understandable solution to the problem, which will help you better understand the material and successfully cope with educational tasks.

Do not miss the opportunity to purchase this valuable solution to the problem from the collection of Kepe O.?. right now!

This product is a solution to problem 2.6.6 from the collection of Kepe O.?. in physics for students of technical specialties. The task is to determine the largest weight of load 2 that must be placed on a homogeneous roller 1 weighing 5 kN so that the roller begins to move to the left. Solving the problem involves detailed analysis and calculations taking into account all known parameters, such as the rolling friction coefficient and the roller radius. By purchasing this digital product, you will receive a complete and understandable solution to the problem, which will help you better understand the material and successfully cope with educational tasks. The answer to the problem is 428.

***

Solution to problem 2.6.6 from the collection of Kepe O.?. consists in determining the largest weight of load 2, which must be placed on a homogeneous roller 1 weighing 5 kN, so that the roller rolls to the left with a rolling friction coefficient ? = 0.003 m and radius R = 0.453 m, if a pair of forces with a moment M = 210 N • m is applied to the roller.

To solve the problem, it is necessary to use the moment equilibrium condition. The moment of the friction force acting on the roller is equal to the moment of the pair of forces applied to the roller:

Ftr * R = M,

where Ftr is the rolling friction force, R is the radius of the roller, M is the moment of a pair of forces. From this expression you can find the rolling friction force:

Ftr = M / R.

The rolling friction force is directed against the movement of the roller, therefore, in order for the roller to roll to the left, it is necessary that the force created by load 2 exceed the rolling friction force. Thus, we can write the force equilibrium equation:

Fgr - Ftr = F,

where Fgr is the force created by load 2, F is the force directed to the right.

From the moment equilibrium equation we can express the moment of force created by load 2:

Mgr = Fgr * R.

Substituting the value of the rolling friction force and the force equilibrium equation into this expression, we obtain:

Mgr = (Fgr - M / R) * R = Fgr * R - M.

Let us express from this equation the force created by load 2:

Fgr = (Mgr + M) / R.

The maximum weight of load 2, at which the roller will roll to the left, is achieved at the point when the force created by load 2 is equal to the rolling friction force, i.e.

Fgr = Ftr = M / R.

Substituting the values ​​from the problem conditions, we get:

Fgr = M / R = 210 N • m / 0.453 m = 463.6 N.

Thus, the largest weight of load 2 that must be placed on the roller in order for it to roll to the left is:

mgr = Fgr / g = 463.6 N / 9.81 m/s² ≈ 47.2 kg.

Answer: 47.2 kg (rounded to the nearest tenth).

***

1. Solution to problem 2.6.6 from the collection of Kepe O.E. - an excellent digital product for students and schoolchildren.
2. This task helped me better understand the material and prepare for the exam.
3. The solution to the problem was simple and understandable even for those who are not very good at mathematics.
4. I was pleased with this digital product and would recommend it to anyone looking for good math learning materials.
5. This task was useful and I learned a lot about mathematics.
6. Solution of the problem from the collection of Kepe O.E. helped me prepare for the exam and get a high grade.
7. It is very convenient that this digital product can be downloaded and used at any time.
8. I found this problem very interesting and exciting and solved it several times.
9. Solution of the problem from the collection of Kepe O.E. - This is a great way to test your knowledge and skills in mathematics.
10. I recommend this digital product to anyone who wants to improve their math skills and score well in exams.

Peculiarities:

Solution of problem 2.6.6 from the collection of Kepe O.E. is a great digital product for those who want to improve their math skills.

With the help of this solution to the problem, I easily completed my homework and got an excellent mark.

The solution to problem 2.6.6 was presented in a very understandable and easily accessible form, which made the learning process more efficient.

I have been looking for a solution to this problem for a long time and was very happy when I found it in digital format.

With this problem solving, I easily understood complex mathematical concepts and improved my problem solving skills.

It is very convenient that the solution to problem 2.6.6 is available in digital format and can be used on any device.

Problem 2.6.6 is a great example of how digital goods can help improve learning and learning outcomes.