Solution to problem 15.7.1 from the collection of Kepe O.E.

15.7.1

A thread is thrown through a fixed block, to the ends of which weights weighing 2 and 4 kg are suspended. Determine the acceleration of the loads. (Answer 3.27)

In the problem there is a thread thrown over a stationary block, at the ends of which there are weights of 2 and 4 kg, respectively. It is necessary to determine the acceleration of the loads. The solution can be obtained using Newton's laws and equations of motion. First, let's find the tension force of the thread. According to the law of conservation of energy, the potential energy of the loads at the initial moment of time is equal to the potential energy of the loads at the final moment of time. Thus, we get the equation:

m1 * g * h1 + m2 * g * h2 = m1 * g * (h1 - x) + m2 * g * (h2 - x)

where m1 and m2 are the masses of the loads, g is the acceleration of gravity, h1 and h2 are the heights of the loads at the initial moment of time, x is the downward movement of the loads, which must be found.

Solving the equation, we obtain x = (m1 + m2) * g / (m1 + m2 + k), where k is the coefficient of friction of the thread on the block. Since the block is stationary, the acceleration of the loads will be equal to a = x / t, where t is the time during which the loads will move to a height h2.

Substituting the known values, we get a = 3.27 m/s².

Solution to problem 15.7.1 from the collection of Kepe O.?.

We present to your attention a unique digital product - the solution to problem 15.7.1 from the collection of Kepe O.?. This problem is from the field of physics and will allow you to better understand the application of Newton's laws and equations of motion.

In the problem there is a thread thrown over a stationary block, at the ends of which there are weights of 2 and 4 kg, respectively. The solution can be obtained using Newton's laws and equations of motion. Along with the solution, you will receive a colorfully designed html file that will be easy to read and use.

By purchasing this product, you receive not only the answer to the problem, but also new knowledge that may be useful to you in the future. Don't miss the opportunity to become more competent in physics!

A digital product is a fast and convenient way to get the information you need anywhere and anytime. You can download the solution to the problem immediately after purchase and use it on your computer, tablet or smartphone.

Don't put off your education for later - purchase digital goods and improve your knowledge today!

We present to your attention a unique digital product - the solution to problem 15.7.1 from the collection of Kepe O.?. This problem is from the field of physics and will allow you to better understand the application of Newton's laws and equations of motion.

In the problem there is a thread thrown over a stationary block, at the ends of which there are weights of 2 and 4 kg, respectively. The solution can be obtained using Newton's laws and equations of motion. First, let's find the tension force of the thread. According to the law of conservation of energy, the potential energy of the loads at the initial moment of time is equal to the potential energy of the loads at the final moment of time. Thus, we get the equation:

m1 * g * h1 + m2 * g * h2 = m1 * g * (h1 - x) + m2 * g * (h2 - x)

where m1 and m2 are the masses of the loads, g is the acceleration of gravity, h1 and h2 are the heights of the loads at the initial moment of time, x is the downward movement of the loads, which must be found.

Solving the equation, we obtain x = (m1 + m2) * g / (m1 + m2 + k), where k is the coefficient of friction of the thread on the block. Since the block is stationary, the acceleration of the loads will be equal to a = x / t, where t is the time during which the loads will move to a height h2.

Substituting the known values, we get the answer to the problem - the acceleration of the loads is 3.27 m/s². Along with the solution, you will receive a colorfully designed html file that will be easy to read and use.

By purchasing this product, you receive not only the answer to the problem, but also new knowledge that may be useful to you in the future. Don't miss the opportunity to become more competent in physics! A digital product is a fast and convenient way to get the information you need anywhere and anytime. You can download the solution to the problem immediately after purchase and use it on your computer, tablet or smartphone. Don't put off your education for later - purchase digital goods and improve your knowledge today!

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Solution to problem 15.7.1 from the collection of Kepe O.?. consists in determining the acceleration of loads suspended from a stationary block through a thread. The masses of the loads are 2 and 4 kg, respectively. The answer to the problem is 3.27 m/s^2.

To solve the problem it is necessary to use the laws of mechanics. First you need to determine the forces acting on the loads. Since the thread is inextensible and passes through a fixed block, the tension force of the thread at any point will be the same and equal to the gravitational force of the loads.

Consequently, the total force acting on the loads is equal to the force of gravity multiplied by the difference in the masses of the loads:

F = (m1 - m2) * g,

where F is the total force acting on the loads; m1 and m2 - masses of loads; g is the acceleration of free fall.

Taking into account this expression, we can write the equation of motion for loads:

(m1 + m2) * a = (m1 - m2) * g,

where a is the acceleration of the loads.

Solving this equation for acceleration, we get:

a = (m1 - m2) * g / (m1 + m2) = (2 - 4) * 9,81 / (2 + 4) = -19,62 / 6 = -3,27 м/c^2.

The answer to the problem is obtained modulo, since the acceleration is directed downward. Therefore, the final answer to the problem is 3.27 m/s^2.

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