Solution to problem 14.3.15 from the collection of Kepe O.E.

Solving the problem of sliding friction coefficient

Suppose that a body, which was given an initial speed of v0 = 5 m/s, slid along a rough horizontal plane and stopped after 1 second. We need to find the sliding friction coefficient.

To solve this problem, we will use the law of conservation of energy. Initially the body had kinetic energy equal to:

I = (mv0^2)/2,

where m is the body mass, v0 is the initial velocity.

After stopping, the kinetic energy of the body becomes zero, and all the energy is spent on overcoming the sliding friction force. So we can write:

μmgd = (mv0^2)/2,

where μ is the coefficient of sliding friction, g is the acceleration of free fall, d is the distance traveled by the body before stopping.

To find the sliding friction coefficient, you need to express it from the equation:

µ = (mv0^2)/(2mgd).

Substituting the known values, we get:

μ = (5^2)/(2*9.81*1) ≈ 0.51.

Answer: sliding friction coefficient is 0.51.

Solution to problem 14.3.15 from the collection of Kepe O..

In the digital goods store you can purchase the solution to problem 14.3.15 from the collection of Kepe O.. This problem concerns the determination of the coefficient of sliding friction of a body on a rough horizontal plane.

After the purchase, you will instantly receive a solution to the problem with a beautiful html design, which includes a step-by-step solution, formulas and a numerical answer.

Please note that the solution to the problem is intended for reference and teaching aid, and not for use as a ready-made homework assignment. Please use it wisely and respect the rules of academic integrity.

In the digital goods store you can purchase the solution to problem 14.3.15 from the collection of Kepe O.?. The task is to determine the sliding friction coefficient of a body on a rough horizontal plane. To solve the problem, the law of conservation of energy is used. After purchasing, you will receive a solution to the problem with a beautiful HTML design, which includes a step-by-step solution, formulas and a numerical answer. Please note that the solution to the problem is intended for reference and teaching aid, and not for use as a ready-made homework assignment. Please use it wisely and respect the rules of academic integrity. Answer to the problem: the coefficient of sliding friction is 0.51.

Solution to problem 14.3.15 from the collection of Kepe O.?. consists in determining the coefficient of sliding friction of a body on a rough horizontal plane. In the problem, the initial speed of the body is known, equal to v0 = 5 m/s, the time during which the body stopped, equal to 1 second, and the acceleration of gravity equal to g = 9.81 m/s².

To solve the problem, the law of conservation of energy is used. Initially, the body had kinetic energy, which after stopping becomes equal to zero, and all the energy is spent on overcoming the sliding friction force. So we can write the equation:

μmgd = (mv0^2)/2,

where μ is the coefficient of sliding friction, m is the mass of the body, d is the distance traveled by the body before stopping.

To determine the sliding friction coefficient, it is necessary to express it from the equation by substituting known values:

μ = (mv0^2)/(2mgd) = (5^2)/(29.811) ≈ 0,51.

Thus, the answer to the problem is 0.51. If you purchase a solution to a problem in a digital goods store, you will receive a step-by-step solution, formulas and a numerical answer with a beautiful html design. However, remember that the solution to the problem is intended for reference and teaching aid, and not for use as a ready-made homework assignment. Please use it wisely and respect the rules of academic integrity.

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Problem 14.3.15 from the collection of Kepe O.?. consists in determining the coefficient of sliding friction of a body on a rough horizontal surface. According to the condition, the body has an initial speed v0 = 5 m/s and stops 1 second after the start of movement.

To solve the problem, you can use the equation of motion of a body: v = v0 - at, where v is the final speed of the body, a is acceleration, t is time of movement. Also, using Newton's laws, we can write the equation for the friction force Ftr = μN, where μ is the sliding friction coefficient, N is the support reaction force.

To determine the coefficient of friction, it is necessary to find the friction force, which can be expressed through acceleration and body mass: Ftr = ma. Knowing that the body has stopped, we can write the equation v = 0, which implies that a = v0/t.

Thus, we obtain the equation for finding the friction coefficient: μ = Ftr/N = ma/mg = a/g, where g is the acceleration of free fall.

Substituting the known values, we get: μ = a/g = v0/(gt) = 5/(9.81*1) ≈ 0.510. The answer coincides with that indicated in the problem statement.

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