Solution to problem 5.6.10 from the collection of Kepe O.E.

5.6.10. Solving the cable tension problem

Let us assume that the plate is in equilibrium. Let's create an equation of moments about the Ox axis:

ΣMox = 0

Where ΣMox is the sum of the moments of forces acting on the plate relative to the Ox axis.

Let's introduce the following notation:

T - cable tension AB, N; a - distance from the axis of rotation to the cable attachment point, m; G - weight of the slab, N; α, β, γ - angles formed by the cable with the vertical at points A, B and C, respectively.

Then the moment of force of the cable AB relative to the Ox axis is equal to:

Ma = T * a * sin(a)

The moment of gravity G relative to the Ox axis is equal to:

Mg = G * a * sin(b)

The moment of the bond force C relative to the Ox axis is equal to:

Mc = G * a * sin(c)

Thus, the moment equation will take the form:

T * a * sin(α) - G * a * sin(β) - G * a * sin(γ) = 0

Solving this equation, we get:

T = G * sin(β) * sin(γ) / sin(α) = 400 Н.

Thus, the tension in cable AB is 400 N.

Solution to problem 5.6.10 from the collection of Kepe O.?.

This digital product is a solution to problem 5.6.10 from the collection of problems in physics by Kepe O.?. The solution was made by a professional teacher and contains a detailed description of all stages of solving the problem.

This solution presents the equation of moments about the Ox axis to determine the tension of the cable AB in a homogeneous plate weighing G = 400 N, which is in equilibrium under the influence of imposed connections.

This solution will be useful for students and schoolchildren studying physics, as well as anyone interested in this topic.

Price: 99 rub.

This product is a solution to problem 5.6.10 from the collection of problems in physics by Kepe O.?. The solution was made by a professional teacher and contains a detailed description of all stages of solving the problem.

In this problem, we consider a homogeneous slab weighing G = 400 N, which is in equilibrium under the influence of imposed bonds. To determine the tension of the cable AB, an equation of moments about the Ox axis is drawn up, which takes into account the tension forces of the cable AB, the force of gravity G and the connection force C.

Based on the calculation results, it turns out that the tension in the cable AB is 400 N. The solution to this problem will be useful for students and schoolchildren studying physics, as well as for everyone who is interested in this topic.

The price of the product is 99 rubles.

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Solution to problem 5.6.10 from the collection of Kepe O.?. consists in determining the tension of the cable AB, if the weight of the homogeneous plate, the imposed connections and the geometric parameters of the system are known.

To solve the problem, it is necessary to create an equation of moments about the Ox axis. Since the system is in equilibrium, the sum of the moments must be zero.

In this case, we have one equation with one unknown:

aFsin(61°) - aFsin(44°) - Ga/2sin(60°) = 0,

where F is the desired tension of the cable AB, a is the distance between points A and B, G is the weight of the homogeneous plate.

Solving the equation, we get:

F = G/2 = 400 Н.

Thus, the desired tension in the cable AB is 400 N.

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