20.6.17 In a mechanics problem, you need to find the generalized acceleration x of a conservative mechanical system with one degree of freedom at the time when x equals 2m. To do this, it is necessary to use the kinetic potential formula, which for a given system takes the form L = 4x² - x⁴ - 6x². Having solved the problem, we get the answer: 7.
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We present to you a digital product in the digital goods store - “Solution to problem 20.6.17 from the collection of Kepe O.?”. This product provides a detailed solution to a mechanical problem that requires finding the generalized acceleration x of a conservative mechanical system with one degree of freedom at the time when x equals 2m. To solve the problem, it is necessary to use the kinetic potential formula, which for a given system takes the form L = 4x² - x⁴ - 6x². The entire product solution is presented in a beautiful html design, which makes it easy to use and allows you to quickly and accurately find the necessary information. The answer to the problem in this case is 7.
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The problem requires finding the generalized acceleration x of a conservative mechanical system with one degree of freedom at the time when x equals 2m. To solve, the formula for the kinetic potential L is used, which for a given system takes the form L = 4x² - x⁴ - 6x².
By purchasing this product, you will receive a complete solution to the problem with a step-by-step description of the formulas and solution methods used. And also, you will receive an answer to this problem, which is 7.
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Solution to problem 20.6.17 from the collection of Kepe O.?. consists in determining the generalized acceleration x at the moment of time when x = 2 meters, for a conservative mechanical system with one degree of freedom, in which the kinetic potential is given by the expression L = 4x^2 - x^4 - 6x^2, where x is the generalized coordinate .
To solve the problem, it is necessary to find the Lagrange equation of the second kind, then calculate the generalized forces equal to the derivative of the Lagrange equation with respect to the generalized coordinate, and substitute the value of the coordinate x = 2 meters into the resulting equation. As a result, we obtain the value of the generalized acceleration x at the moment of time when x = 2 meters, which is equal to 7.
Thus, to solve this problem, you must complete the following steps:
Lagrange = d/dt(dL/dx_dot) - dL/dx,
where L is the kinetic potential of the system, x_dot is the derivative of the generalized coordinate with respect to time.
dL/dx_dot = 8x_dot - 4x_dot^3
dL/dx = 8x - 4x^3 - 12x
Lagrange = d/dt(8x_dot - 4x_dot^3) - (8x - 4x^3 - 12x)
d/dt(dL/dx_dot) = d^2x/dt^2(8 - 12x^2)
d^2x/dt^2(8 - 12x^2) - (8x - 4x^3 - 12x) = 0
Solve the resulting differential equation using the initial conditions specified in the problem statement.
Substitute the value x = 2 meters into the resulting solution and calculate the generalized acceleration x at the time when x = 2 meters. The answer should be 7.
Thus, the solution to problem 20.6.17 from the collection of Kepe O.?. consists in finding the generalized acceleration x at the time when x = 2 meters, for a conservative mechanical system with one degree of freedom, whose kinetic potential is given by the expression L = 4x^2 - x^4 - 6x^2.
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