Solution to problem 8.3.10 from the collection of Kepe O.E.

8.3.10 The angular velocity of a body changes according to the law? = 2t3. Determine the tangential acceleration of a point of this body at a distance r = 0.2 m from the axis of rotation at time t = 2 s. (Answer 4.8)

To solve this problem, it is necessary to determine the value of the angular acceleration of the body at the moment of time t=2s. To do this, you need to take the derivative of the law of change in angular velocity with time:

$\alpha = \frac{d\omega}{dt} = 6t^2$

Then, using the formula for the tangential acceleration of a point, you can find its value at time t=2s at a distance r=0.2m from the axis of rotation:

$a_t = r\alpha = 0,2м \cdot 6 \cdot 2^2 = 4,8м/c^2$

Thus, the tangential acceleration of a point of the body at a distance of 0.2 m from the axis of rotation at the moment of time t=2s is equal to 4.8 m/s^2.

Solution to problem 8.3.10 from the collection of Kepe O.?.

This digital product is a solution to problem 8.3.10 from the collection of problems in physics by Kepe O.?. The solution to this problem is presented in the form of a beautifully designed HTML document that is easy to read and understand.

To solve the problem, a formula is used to determine the tangential acceleration of a point of a body at a distance r from the axis of rotation at time t. The solution involves calculating the angular acceleration of the body and then finding the tangential acceleration of the point.

This digital product is ideal for students and teachers studying physics or preparing for exams. It is a convenient and accessible source of information that can be used for learning and self-study.

Buy this digital product and get access to a high-quality solution to the problem from the collection of Kepe O.?. in a beautifully designed HTML format.

Price: 99 rub.

In this digital goods store you can purchase a solution to problem 8.3.10 from the collection of problems in physics by Kepe O.?. This digital product is presented in a beautifully designed HTML document that is easy to read and understand. Solving the problem involves calculating the angular acceleration of the body and then finding the tangential acceleration of the point. It is a convenient and accessible source of information that can be used for learning and self-study. This product is ideal for students and teachers studying physics or preparing for exams. By purchasing this digital product, you will get access to a high-quality solution to the problem from the collection of Kepe O.?. in a beautifully designed HTML format at a price of 99 rubles.

This product is a solution to problem 8.3.10 from the collection of problems in physics by Kepe O.?. The solution to this problem is presented in the form of a beautifully designed HTML document that is easy to read and understand. To solve the problem, a formula is used to determine the tangential acceleration of a point of a body at a distance r from the axis of rotation at time t. The solution involves calculating the angular acceleration of the body and then finding the tangential acceleration of the point.

This product is ideal for students and teachers studying physics or preparing for exams. It is a convenient and accessible source of information that can be used for learning and self-study. By purchasing this digital product, you will get access to a high-quality solution to the problem from the collection of Kepe O.?. in a beautifully designed HTML format at a price of 99 rubles.

To solve the problem, it is necessary to determine the value of the angular acceleration of the body at the time t=2s. To do this, you need to take the derivative of the law of change in angular velocity with time: $\alpha = \frac{d\omega}{dt} = 6t^2$. Then, using the formula for the tangential acceleration of a point, you can find its value at time t=2s at a distance r=0.2m from the axis of rotation: $a_t = r\alpha = 0.2m \cdot 6 \cdot 2^2 = 4 .8m/s^2$.

Thus, the tangential acceleration of a point of the body at a distance of 0.2 m from the axis of rotation at the moment of time t=2s is equal to 4.8 m/s^2.


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The product is the solution to problem 8.3.10 from the collection of Kepe O.?. The task is to determine the tangential acceleration of a point of a body at a distance of 0.2 m from the axis of rotation at the moment of time t = 2 s, provided that the angular velocity of the body changes according to the law? = 2t3. To solve the problem, it is necessary to calculate the derivative of the angular velocity with respect to time, then multiply it by the distance to the axis of rotation. The result obtained will be the tangential acceleration of a point of the body at the specified distance. The answer to the problem is 4.8.


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  2. I am grateful to the author for such a useful problem and its solution.
  3. This solution to the problem turned out to be very clear and accessible even for those who are just starting to study the topic.
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  6. I would recommend this solution to the problem to anyone who wants to deepen their knowledge of probability and statistics.
  7. Many thanks to the author for the detailed and clear solution to the problem from the collection of Kepe O.E.



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