Slotting machine with motor power equal to N

Consider a slotting machine whose motor power is N = 480 W. In time t = 5 minutes, the machine cuts a groove with a depth of h = 18 mm and a length of l = 100 mm. It is necessary to determine the efficiency of the machine drive, that is, the ratio of cutting work to the energy consumed by the machine.

To solve this problem it is necessary to find the cutting work. The cutting work Wр can be determined by the formula:

Wр = Fр * l * h

where Fр is the cutting force, l is the length of the groove, h is the depth of the groove.

For this task Fр = 1 kN, l = 100 mm, h = 18 mm. Substituting the values ​​into the formula, we get:

Wр = 1 kN * 100 mm * 18 mm = 1800 J

?energy consumed by the machine during time t = 5 minutes is equal to:

Eп = N * t * 60

where t is time in seconds.

Substituting the values, we get:

Power = 480 W * 5 min * 60 s/min = 144000 J

Now you can determine the efficiency of the machine drive using the formula:

Efficiency = Wr / Ep * 100%

Substituting the values, we get:

Efficiency = 1800 J / 144000 J * 100% = 1.25%

Thus, the efficiency of the machine drive is 1.25%. This means that only 1.25% of the energy consumed by the machine is used for cutting work, with the rest going to other processes such as friction and heat production.

This slotting machine has a motor power of N = 480 W. In time t = 5 minutes, the machine cuts a groove with a depth of h = 18 mm and a length of l = 100 mm. It is necessary to determine the efficiency of the machine drive, that is, the ratio of cutting work to the energy consumed by the machine. The increase in groove depth per one pass of the cutter, equal to l, is 0.5 mm, and the cutting force Fр = 1 kN.

To determine the efficiency of the machine drive, it is necessary to find the cutting work, which is calculated by the formula Wр = Fр * l * h, where Fр is the cutting force, l is the length of the groove, h is the depth of the groove. Substituting the known values, we find that the cutting work Wр is equal to 1800 J.

?energy consumed by the machine during time t = 5 minutes is equal to Ep = N * t * 60. Substituting the values, we find that Ep is equal to 144000 J.

Using data on cutting operation and energy consumption by the machine, the drive efficiency can be determined using the formula efficiency = Wр / Ep * 100%. Substituting the values, we find that the efficiency of the machine drive is 1.25%. This suggests that only 1.25% of the energy consumed by a machine tool is used for cutting work, with the rest going to other processes such as friction and heat production.

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This slotting machine has a motor power of N = 480 W and in a time t = 5 minutes it cuts a groove with a depth of h = 18 mm and a length of l = 100 mm. The increase in groove depth per one pass of the cutter, equal to l, is 0.5 mm, and the cutting force Fр = 1 kN.

To determine the efficiency of the machine drive, it is necessary to find the cutting work, which is calculated by the formula Wр = Fр * l * h, where Fр is the cutting force, l is the length of the groove, h is the depth of the groove. Substituting the known values, we find that the cutting work Wр is equal to:

Wр = 1 kN * 100 mm * 18 mm = 1800 J.

?energy consumed by the machine during time t = 5 minutes is equal to Ep = N * t * 60, where t is time in seconds. Substituting the values, we find that Ep is equal to:

Power = 480 W * 5 min * 60 s/min = 144000 J

Using data on cutting operation and energy consumption by the machine, the drive efficiency can be determined using the formula:

Efficiency = Wr / Ep * 100%.

Substituting the values, we find that the efficiency of the machine drive is:

Efficiency = 1800 J / 144000 J * 100% = 1.25%.

Thus, only 1.25% of the energy consumed by the machine is used for cutting work, and the rest is spent on other processes such as friction and heat production.

This slotting machine is a powerful and reliable device that provides high productivity and quality of work. By purchasing this device from a digital store, you get a high-quality slotting machine with a powerful motor and the ability to quickly create grooves in materials of varying hardness and density. Beautiful html design of the store allows you to quickly and conveniently buy a slotting machine and enjoy its high productivity and accuracy.

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A slotting machine is a special piece of equipment designed to create grooves in various materials. In this case, we consider a machine with a motor power of N = 480 W.

In time t = 5 minutes, the machine cuts a groove with a depth of h = 18 mm and a length of l = 100 mm. Considering that the increase in groove depth per pass is 0.5 mm, we can determine the number of cutter passes required to cut a groove of full depth: h / 0.5 = 36. Therefore, the total length of the groove cut by the machine is l * 36 = 3600 mm = 3.6 m.

The cutting force is Fр = 1 kN. In this case, it is necessary to determine the efficiency of the machine drive, that is, the ratio of cutting work to the energy consumed by the machine. To do this you need to use the formula:

η = (Fр * l * n) / (P * t)

where η is the efficiency of the machine drive, Fр is the cutting force, l is the stroke length of the cutter, n is the number of cuts of the cutter, P is the power of the machine engine, t is the operating time of the machine.

Substituting known values, we get:

n = (1 * 100 * 36) / (480 * 5) = 0.15

Thus, the efficiency of the machine drive is 0.15 or 15%.

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