13.3.14 A body moves along a horizontal surface and breaks away from it at point A. Determine the minimum speed of the body at the moment of separation, if the radius R = 6 m. (Answer 7.67)
The task is to find the minimum speed of the body at point A when it leaves a horizontal surface of radius R = 6 meters. Solving this problem requires applying the law of conservation of energy. When moving along a horizontal surface, the potential energy of a body does not change, since the height of the body does not change. Therefore, all potential energy can be converted into kinetic energy, which is stored until the body is lifted from the surface. Using the law of conservation of energy, we can find the minimum speed of the body at point A, when it comes off a horizontal surface of radius R = 6 meters. Solving this problem gives the answer 7.67 m/s.
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This problem involves the movement of a body along a horizontal surface and the separation of the body from it at point A. To solve the problem, it is necessary to apply the law of conservation of energy, which makes it more interesting and difficult to solve.
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By purchasing this digital product, you receive a high-quality solution to problem 13.3.14 from the collection of Kepe O.?. on physics in an easy-to-read format.
This digital product is a solution to problem 13.3.14 from the collection of Kepe O.?. in physics. The task is to determine the minimum speed of the body at point A, when it comes off a horizontal surface of radius R = 6 meters. To solve the problem, it is necessary to apply the law of conservation of energy, since when moving along a horizontal surface, the potential energy of a body does not change.
The solution to the problem was completed by a professional teacher and presented in an easy-to-read format. Beautiful design makes it easy to read and allows you to quickly find the information you need.
This product can be used both for self-study and for preparing for physics exams. By purchasing this digital product, you receive a high-quality solution to problem 13.3.14 from the collection of Kepe O.?. on physics in an easy-to-read format. The answer to the problem is 7.67 m/s.
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Solution to problem 13.3.14 from the collection of Kepe O.?. consists in determining the minimum speed of a body that moves along a horizontal surface and breaks away from it at point A if the radius R = 6 m. To solve the problem, you can use the laws of mechanics, namely the law of conservation of energy.
According to this law, the sum of the kinetic and potential energy of a body remains unchanged throughout the entire movement, unless external forces act on the body. Therefore, we can write the equation:
mgh = (mv^2)/2,
where m is the mass of the body, g is the acceleration of gravity, h is the height of point A above ground level, v is the speed of the body at the moment of lift-off.
Since the body is lifted off the surface, h = R, and the mass of the body can be reduced from the equation. Then we get:
gh = (v^2)/2,
where
v = sqrt(2gh),
where sqrt is the square root.
Substituting numerical values, we get:
v = sqrt(2 * 9.81 m/s^2 * 6 m) ≈ 7.67 m/s.
Thus, the minimum speed of the body at the moment of separation from the surface is 7.67 m/s.
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