The speed of water flow in a certain section is horizontal

Given: the speed of water flow in a horizontal pipe is 5 cm/s.

Find: the flow velocity in a section of pipe with half the diameter and in a section with half the cross-sectional area.

Let's consider the law of conservation of mass for a liquid moving in a pipe. According to this law, the volume of liquid passing through one section per unit time must be equal to the volume of liquid passing through any other section during the same time. Therefore, the speed of fluid flow is inversely proportional to the cross-sectional area of ​​the pipe.

Thus, if the diameter of a pipe is halved, its cross-sectional area will decrease fourfold, and the fluid flow rate will double. Likewise, if the cross-sectional area of ​​a pipe is halved, the velocity of the fluid will double.

Thus, the flow speed in a section of a pipe with half the diameter will be 10 cm/s, and in a section with half the cross-sectional area it will also be 10 cm/s.

Product description: "The speed of water flow in a certain section of a horizontal pipe"

This digital product is a unique material that will help you understand issues related to the speed of fluid flow in a horizontal pipe.

In this product you will find a detailed description of the law of conservation of mass for a fluid moving in a pipe, as well as detailed explanations and examples of calculating the speed of fluid flow in various sections of the pipe.

All material is presented in a beautiful html format, which makes it convenient and enjoyable to read. You can save this digital product on your computer or mobile device and use it at any time to solve problems and calculations related to the speed of fluid flow in horizontal pipes.

Don't miss the opportunity to purchase this unique product and improve your knowledge in the field of fluid dynamics!

This product is a digital material that will help you understand issues related to the speed of fluid flow in a horizontal pipe. In this product you will find a detailed description of problem 10767, which involves finding the speed of water flow in that part of the pipe that has half the diameter and half the cross-sectional area, given the known speed of water flow in a horizontal pipe (5 cm/s).

In this product you will find a detailed description of the law of conservation of mass for a fluid moving in a pipe, as well as detailed explanations and examples of calculating the speed of fluid flow in various sections of the pipe. You will learn that the speed of fluid flow is inversely proportional to the cross-sectional area of ​​the pipe. Thus, if the diameter of a pipe is halved, its cross-sectional area will decrease fourfold, and the fluid flow rate will double. Likewise, if the cross-sectional area of ​​a pipe is halved, the velocity of the fluid will double.

In this product you will find a solution to problem 10767 with a detailed description of the formulas and laws used in the solution, the derivation of the calculation formula and the answer. If you have any questions about the solution, you can contact the author and get help. The product is designed in a beautiful html format, which makes it convenient and enjoyable to read. You can save this digital product on your computer or mobile device and use it at any time to solve problems and calculations related to the speed of fluid flow in horizontal pipes. Don't miss the opportunity to purchase this unique product and improve your knowledge in the field of fluid dynamics!


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This product is a solution to problem 10767, related to determining the speed of water flow in a horizontal pipe. The problem statement states that the speed of water flow in a certain section of a horizontal pipe is 5 cm/s. It is required to find the flow velocity in that part of the pipe that has half the diameter, as well as in that part that has half the cross-sectional area.

To solve the problem it is necessary to use the laws of conservation of mass and energy. From the law of conservation of mass it follows that the liquid flow rate in the pipe does not change, that is, Q = const, where Q is the liquid flow rate. From the law of conservation of energy it follows that the sum of the kinetic and potential energy of the liquid in different parts of the pipe must be the same.

To find flow rates in different parts of the pipe, you can use the formula for fluid flow through the pipe Q = v * S, where v is the fluid flow rate, S is the cross-sectional area of ​​the pipe.

For a pipe with half the diameter, the cross-sectional area will be four times smaller, so the fluid flow speed in this part of the pipe will be four times greater and equal to 20 cm/s.

For a pipe with half the cross-sectional area, the fluid flow speed will be twice as large and equal to 10 cm/s.

Thus, the answer to the problem consists of two values ​​of fluid flow velocity: 20 cm/s and 10 cm/s.


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