Solution to problem 16.1.6 from the collection of Kepe O.E.

Problem 16.1.6 sounds like this: there is a cone with mass m = 10 kg and base radius R = 1 m, which rotates around the axis of symmetry according to the law? = 4sin 2t. It is necessary to determine the main moment arising due to external forces acting on the cone relative to the axis of rotation at time t = ?/4 s. The moment of inertia of the cone Iz is 0.3 mR2. The answer to the problem is -48.

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Solution to problem 16.1.6 from the collection of Kepe O.?. consists in determining the main moment of external forces applied to the cone relative to the axis of rotation at the moment of time t = ?/4.

To solve the problem it is necessary to use the law of conservation of angular momentum. The main moment M of the load can be expressed as the product of the moment of inertia I and the angular acceleration α of the cone: M = Iα.

Angular acceleration can be found from the equation of motion of a rotating body: α = dω/dt, where ω is the angular velocity determined from the law of cone rotation using the formula ω = dθ/dt = 8cos(2t).

Differentiating the expression for angular velocity with respect to time, we obtain: α = dω/dt = d(8cos(2t))/dt = -16sin(2t).

Now, substituting the values ​​of the cone mass m = 10 kg, base radius R = 1 m, moment of inertia of the cone Iz = 0.3 mR^2 and angular acceleration α = -16sin(2t) into the formula for the main moment, we obtain:

M = Iz * α = 0.3 * 1^2 * (-16sin(2t)) = -4.8sin(2t).

The sought main moment at time t = ?/4 seconds is equal to M = -4.8sin(2*π/4) = -4.8sin(π) = -4.8 * 0 = 0 Nm.

Thus, the answer to problem 16.1.6 from the collection of Kepe O.?. - the main moment of external forces applied to the cone relative to the axis of rotation at the moment of time t = ?/4 s is equal to 0 Nm.


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