Solution to problem 14.1.3 from the collection of Kepe O.E.

14.1.3 A body with mass m = 2 kg moves along horizontal guides according to the law s = 2t2 + 1.

It is necessary to determine the module of the main vector of external forces acting on the body.

Answer: 8

Let's consider this problem. From the condition it is known that a body with a mass of 2 kg moves horizontally and is described by the equation $s = 2t^2 + 1$. To find the module of the main vector of external forces, it is necessary to use Newton's second law: $\vec{F} = m\vec{a}$, where $\vec{F}$ is the force vector, $m$ is the body mass, $\ vec{a}$ - acceleration of the body.

Since the body moves along a horizontal straight line, its acceleration is equal to the time derivative of the equation $s = 2t^2 + 1$: $a=\frac{d^2s}{dt^2}=4$. Therefore, the external force acting on the body is equal to $\vec{F} = m\vec{a} = 2 \cdot 4 = 8$ N. Answer: 8.

Solution to problem 14.1.3 from the collection of Kepe O.?.

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Solution to problem 14.1.3 from the collection of Kepe O.?. consists in determining the module of the main vector of external forces acting on a body of mass 2 kg, which moves along horizontal guides according to the law s = 2t^2 + 1.

To solve the problem, it is necessary to use Newton’s second law, which states that the force acting on a body is equal to the product of the body’s mass and its acceleration: F = m*a.

The acceleration of the body can be found by taking the second derivative of the law of motion s = 2t^2 + 1: a = 4 m/s^2.

Then, substituting the value of the body mass and its acceleration into Newton’s second law, we obtain: F = m*a = 2 kg * 4 m/s^2 = 8 N.

Thus, the module of the main vector of external forces acting on the body is equal to 8 N.


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