Solution C2-73 (Figure C2.7 condition 3 S.M. Targ 1989)

Solution to problem C2-73 from the textbook by S.M. Targa (1989):

Given a structure consisting of a rigid angle and a rod, connected to each other by hinges or freely resting on each other at point C. External connections are a hinge or a rigid seal at point A, a smooth plane or weightless rod BB´ or a hinge at point B, and a weightless rod DD´ or a hinged support on rollers at point D. The structure is acted upon by a pair of forces with a moment M = 60 kN m, a uniformly distributed load of intensity q = 20 kN/m and two more forces indicated in table C2 with their directions and application points. The loaded area is also indicated in Table C2.

It is necessary to determine the reactions of the connections at points A, B, C (and at point D for Figures 0, 3, 7, 8) caused by the given loads. For final calculations, a = 0.2 m is accepted.

Let us present a solution to this problem. First, let's draw a force diagram and designate all the forces acting on the structure. Then we will divide the structure into individual elements and calculate the reactions of the connections at each point.

For picture 0:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, FxB = 20 a = 4 kN, MzB = 0.

At point C: FyC = -20, FxC = -20, MzC = 0.

For Figure 1:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, FxB = 0, MzB = 0.

At point C: FyC = -20, FxC = -20, MzC = 0.

For Figure 2:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, FxB = -20 a = -4 kN, MzB = 0.

At point C: FyC = -20, FxC = 20, MzC = 0.

For Figure 3:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, FxB = -20 a = -4 kN, MzB = 0.

At point C: FyC = -20, FxC = 20, MzC = 0.

B to D: FyD = 0, FxD = 0, MzD = 0.

For Figure 4:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 20, FxB = 0, MzB = 0.

At point C: FyC = -20, FxC = 0, MzC = 0.

For Figure 5:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 20, FxB = 0, MzB = 0.

At point C: FyC = -20, FxC = 0, MzC = 0.

For Figure 6:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, FxB = 0, MzB = 0.

At point C: FyC = -20, FxC = -20, MzC = 0.

For Figure 7:

Power diagram:

We break the structure into elements and calculate the reactions of the connections:

At point A: FyA = 0, MzA = -M = -60 kN m.

At point B: FyB = 0, F

This product is a solution to problem C2-73 from the textbook “Strength of Materials” by author S.M. Targa, released in 1989. The solution refers to Figure C2.7 condition 3 and includes a detailed force diagram, as well as a calculation of the reactions of the bonds at points A, B, C and D at given loads.

The product is presented in a beautifully designed HTML page, making it easy to view and use. All calculations were carried out using appropriate formulas and methods, which guarantees the accuracy and reliability of the results.

This product is intended for students and teachers studying the strength of materials, as well as for anyone interested in this topic. Solving the problem will help you better understand the theoretical aspects and consolidate the acquired knowledge in practice.

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Solution C2-73 is a structure consisting of a rigid angle and a rod, connected to each other by hinges or freely supported by each other at point C. The structure has external connections that are imposed at points A and B, as well as at point D for some options. At point A, the structure can be connected either by a hinge or by a rigid connection. At point B, the structure can rest on a smooth plane, on a weightless rod BB´ or on a hinge. At point D, the structure can rest on a weightless rod DD´ or on a hinged support on rollers.

The structure is acted upon by a pair of forces with a moment M = 60 kN m, a uniformly distributed load of intensity q = 20 kN/m, and two more forces. The directions and points of application of these forces are indicated in Table. C2, and also indicates in which area the distributed load acts.

The task is to determine the reactions of connections at points A, B, C and D (for some options) caused by given loads. When calculating, you should take a = 0.2 m.

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