Solution K1-32 (Figure K1.3 condition 2 S.M. Targ 1989)

Task K1-32 (Figure K1.3 condition 2 S.M. Targ 1989) includes two tasks: K1a and K1b, which must be solved.

Problem K1a. Point B moves on the xy plane (Fig. K1.0 - K 1.9, Table K1). The trajectory of the point is shown conventionally in the figures. The law of motion of a point is given by the equations: x = f1(t), y = f2(t), where x and y are expressed in centimeters, t in seconds. It is necessary to find the equation of the trajectory of the point, and also determine the speed and acceleration of the point at the time t1 = 1 s, its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x = f1(t) is indicated directly in the figures, and the dependence y = f2(t) is given in the table. K1 (for Fig. 0-2 in column 2, for Fig. 3-6 in column 3, for Fig. 7-9 in column 4). The figure number is selected according to the penultimate digit of the code, and the condition number in the table. K1 - according to the last one.

Problem K1b. The point moves along a circular arc of radius R = 2 m according to the law s = f(t), given in table. K1 in column 5 (s - in meters, t - in seconds), where s = AM is the distance of the point from the beginning of A, measured along the arc of a circle. It is necessary to determine the speed and acceleration of the point at the moment t1 = 1 s, and also depict the vectors v and a in the figure, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

"Solution K1-32 (Figure K1.3 condition 2 S.M. Targ 1989)" is a digital product that represents a solution to a problem from the textbook by S.M. Targa "Movement of a point." The solution contains a detailed description of problem K1-32 and its solution, as well as graphic images for a visual representation of the trajectory of the point, the speed and acceleration of the point at the corresponding times.

Problem K1-32 consists of two parts: K1a and K1b, each of which is solved in stages. In problem K1a, it is necessary to find the equation for the trajectory of a point, as well as determine the speed and acceleration of the point at time t1 = 1 s, its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. In problem K1b, it is necessary to determine the speed and acceleration of a point at time t1 = 1 s, and also to depict vectors v and a in the figure.

All information in the solution is accompanied by graphic images for a better understanding of the solution to the problem. Beautiful html design in a digital goods store allows you to see all the advantages of the solution and quickly and easily place an order. The key to access the solution will be sent by email immediately after payment. Customers will be able to quickly access the solution and use it for training purposes.

"Solution K1-32 (Figure K1.3 condition 2 S.M. Targ 1989)" is a digital product that contains the solution to problem K1-32 from the textbook by S.M. Targa "Movement of a point." The task consists of two parts: K1a and K1b.

In problem K1a, it is necessary to find the equation of the trajectory of a point, the speed and acceleration of the point at time t1 = 1 s, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. To do this, the laws of motion of a point along the x and y axes are specified, which are expressed in centimeters and seconds. The dependence x = f1(t) is indicated directly in the figures, and the dependence y = f2(t) is given in the table. K1.

In problem K1b it is necessary to determine the speed and acceleration of a point at time t1 = 1 s. The point moves along a circular arc of radius R = 2 m according to the law s = f(t), given in table. K1 in column 5 (s - in meters, t - in seconds), where s = AM is the distance of a point from some origin A, measured along the arc of a circle. It is also necessary to depict vectors v and a in the figure, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

The solution to problem K1-32 is accompanied by graphic images for a visual representation of the trajectory of the point, the speed and acceleration of the point at the corresponding moments of time. The key to access the solution will be sent by email immediately after payment. The solution can be used for educational purposes.

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Solution K1-32 is a problem consisting of two parts - K1a and K1b. In part K1a, point B moves in the xy plane. The equations describing its movement are given: x = f1(t) and y = f2(t), where x and y are expressed in centimeters, t - in seconds. It is necessary to find the equation of the trajectory of the point, calculate the speed and acceleration of the point at the time t1 = 1 s, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x = f1(t) is indicated in the figures, and the dependence y = f2(t) is given in table K1.

In part K1b, the point moves along an arc of a circle of radius R = 2 m according to the law s = f(t), given in table K1 in column 5 (s - in meters, t - in seconds), where s = AM is the distance of the point from some origin A, measured along the arc of a circle. It is necessary to determine the speed and acceleration of the point at time t1 = 1 s. In the figure, it is necessary to depict the vectors v and a, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

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