Solution to problem 9.7.6 from the collection of Kepe O.E.

9.7.6 A wheel of radius r = 0.1 m rolls without slipping. It is necessary to determine the acceleration of point B if the center of wheel A moves at a constant speed vA = 2 m/s. (Answer 40)

The problem is given to determine the acceleration of point B of a wheel that rolls without slipping. To do this, you need to use the formula for the acceleration of a point when moving in a circle: a = v^2 / r, where a is the acceleration of the point, v is the speed of the point, r is the radius of the circle. In this case, the wheel radius r is 0.1 m, and the speed of the wheel center vA is 2 m/s. Since the wheel rolls without slipping, the speed of point B is equal to the speed of the center of the wheel vA. Then the acceleration of point B will be equal to a = vA^2 / r = 2^2 / 0.1 = 40 (m/s^2).

Solution to problem 9.7.6 from the collection of Kepe O.?.

This digital product is a solution to problem 9.7.6 from the collection of problems in physics by Kepe O.?. The solution to the problem is made using formulas and principles of physics, and also contains detailed calculations and explanations of each step.

The problem is to determine the acceleration of point B of a wheel that is rolling without slipping. The radius of the wheel r is 0.1 m, and the speed of the center of the wheel vA is 2 m/s. The solution to the problem is carried out in accordance with the formula for the acceleration of a point when moving in a circle: a = v^2 / r.

By purchasing this digital product, you receive a complete and understandable solution to problem 9.7.6 from the collection of Kepe O.?., which will help you better understand and remember the principles of physics and apply them in practice.

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This digital product is a solution to problem 9.7.6 from the collection of problems in physics by Kepe O.?. The problem is to determine the acceleration of point B of a wheel of radius r=0.1 m, which rolls without slipping, at a constant speed of the wheel center vA=2 m/s. The solution to the problem is made using formulas and principles of physics, and also contains detailed calculations and explanations of each step.

To determine the acceleration of point B, the formula for the acceleration of a point when moving in a circle was used: a = v^2 / r, where a is the acceleration of the point, v is the speed of the point, r is the radius of the circle. Since the wheel rolls without slipping, the speed of point B is equal to the speed of the center of the wheel vA. Substituting these values ​​into the formula, it was found that the acceleration of point B is equal to 40 (m/s^2).

By purchasing this digital product, you receive a complete and understandable solution to the problem, which will help you better understand and remember the principles of physics and apply them in practice. The solution is presented in a beautiful html design, which makes it convenient and enjoyable to read. You can purchase this product on our digital goods store website.

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Solution to problem 9.7.6 from the collection of Kepe O.?. consists in determining the acceleration of point B of a wheel of radius r = 0.1 m, provided that the center of wheel A moves at a constant speed vA = 2 m/s, and the wheel rolls without slipping.

To solve this problem, it is necessary to use formulas that describe the motion of a body in a circle without sliding. In particular, it is known that the speed of point B of the wheel touching the ground is equal to vB = r * ω, where ω is the angular speed of rotation of the wheel.

It is also known that angular acceleration α is related to linear acceleration a as follows: a = r * α.

From the conditions of the problem it follows that the center of the wheel moves uniformly, that is, its speed is constant and equal to vA = 2 m/s.

Thus, by solving a system of equations connecting angular velocity, linear acceleration and the speed of the center of the wheel, we can find the acceleration of point B.

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