Solution of problem 2.6.12 from the collection of Kepe O.E.

2.6.12 The problem considers a homogeneous roller with a small radius of 0.2 m, on which a load weighing 200 N is suspended. A pair of forces is applied to the roller, creating a moment M = 57.6 N m. It is necessary to determine the maximum weight of the roller in kN at which it will move to the left if the rolling friction coefficient is equal to? = 0.008 m. The answer to the problem is 2.0 kN.

Solution: The friction force arising when the roller rolls is equal to Ftr = ?N, where N is the support reaction, and ? - rolling friction coefficient. The problem statement states that? = 0.008 m. Then Ftr = 0.008N.

The moment of force M is created by a pair of forces applied to the roller at a distance r = 0.2 m from its axis. This means M = Fr, where F is the force applied to the roller. Then F = M/r = 57.6/0.2 = 288 N.

The sum of the forces acting on the roller is zero, since the roller moves uniformly. It follows from this that N = Fgr, where Fgr is the weight of the load suspended on the roller. The problem statement states that Fgr = 200 N. Then N = 200 N.

Let us find the equilibrium condition for the roller under which it does not start moving to the right or left. To do this, we compare the moments of forces acting on the skating rink. The moment of force Fgr is equal to zero, since its point of application is on the axis of the roller. The moment of force Ftr is equal to Ftrr = 0,008200*0.2 = 3.2 N·m.

The moment of force M creates rotation of the roller to the left. Therefore, the equilibrium condition can be written as the equation M = Ftr*r, from which we obtain the weight of the roller:

N = Fgr + Ftr = Fgr + ?N = Fgr/(1-?) = 200/(1-0.008) = 204.1 N.

The answer to the problem is 2.0 kN, which corresponds to 204.1 N divided by 1000 (since 1 kN = 1000 N).

Solution to problem 2.6.12 from the collection of Kepe O.?.

This digital product is a solution to problem 2.6.12 from the collection of problems in physics by Kepe O.?. The problem considers a homogeneous roller with a small radius of 0.2 m, on which a load weighing 200 N is suspended. A pair of forces is applied to the roller, creating a moment M = 57.6 N m. It is necessary to determine the maximum weight of the roller in kN at which it will move to the left if the rolling friction coefficient is equal to? = 0.008 m.

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Digital product - solution to problem 2.6.12 from the collection of problems in physics by Kepe O.?. The product description states that the solution contains a detailed description of all the steps, formulas and calculations necessary to obtain the correct answer to the problem. It is also noted that the solution is presented in a beautiful HTML format, which makes it easy to read and use in preparation for exams or testing in physics. The solution to the problem concerns a homogeneous roller with a small radius of 0.2 m, on which a load weighing 200 N is suspended. A pair of forces is applied to the roller, creating a moment M = 57.6 N m. It is necessary to determine the maximum weight of the roller in kN at which it will move to the left if the rolling friction coefficient is equal to? = 0.008 m. The answer to the problem is 2.0 kN.

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The proposed product offer is a solution to problem 2.6.12 from the collection of Kepe O.?.

This problem considers a roller on which a load weighing 1 kilogram is suspended and which is applied to a force with a moment of 57.6 N m. The radius of the roller is also known - 0.2 m and the coefficient of rolling friction - 0.008 m. It is necessary to determine the maximum weight of the roller at which it will roll to the left.

Solving this problem requires the application of the laws of mechanics and formulas related to body rolling. After performing a number of mathematical operations, you can get the answer to the question posed - the largest weight of the roller at which it will roll to the left is 2.0 kN.

The solution to this problem can be useful for students studying physics and mechanics, as well as teachers, who can use it as an example when preparing for exams and knowledge testing.

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