2.4.14 Consider a pendulum that is in a state of equilibrium under the action of two pairs of forces. The first pair of forces has a moment M = 0.5 N m, and the second pair of forces is formed by the weight G and the support reaction R. If it is known that the value of the weight G is 10 N, and the distance to the center of mass of the pendulum is l = 0.1 m, then what value of the angle of deflection of the pendulum in degrees can we determine? The answer to this question is 30.0 degrees.
This digital product is a solution to problem 2.4.14 from the collection of Kepe O.?. in physics.
The problem is to determine the angle of deflection of a pendulum that is in equilibrium under the action of two pairs of forces. The solution to this problem contains a detailed analysis and step-by-step description of the applied formulas and solution methods.
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Solution to problem 2.4.14 from the collection of Kepe O.?. consists in finding the angle of deflection of the pendulum in degrees, if the parameters of the pair of forces acting on the pendulum in equilibrium are known.
It is given that the moment of the pair of forces is equal to M = 0.5 N m, weight G = 10 N, and the distance from the suspension point to the center of gravity of the pendulum is l = 0.1 m. It is required to find the angle of deflection of the pendulum.
To solve the problem, you can use the equilibrium condition of the pendulum, which is that the sum of the moments of all forces acting on the pendulum is equal to zero. Taking this condition into account, we can create the equation:
М = G * l * sin(?),
where M is the moment of a pair of forces, G is the weight of the pendulum, l is the distance from the suspension point to the center of gravity of the pendulum, and ? - angle of deflection of the pendulum.
Solving the equation, we get:
sin(?) = M / (G * l) = 0.5 N m / (10 N * 0.1 m) = 0.5.
From here we find the angle ?:
? = arcsin(0.5) ≈ 30.0 degrees.
Thus, the answer to problem 2.4.14 from the collection of Kepe O.?. is 30.0 degrees.
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