Solution to problem 17.4.15 from the collection of Kepe O.E.

17.4.15 Question about the rotor speed of an electric motor weighing 400 kg, which is equal to 3000 rpm. What is the maximum permissible displacement of the main central axis of inertia of the rotor from the axis of rotation so that the dynamic reaction of the bearing does not exceed the value R = 400 N? Point C represents the center of mass of the rotor. (Answer: 0.0203)

When the rotor of an electric motor rotates at 3000 rpm and has a mass of 400 kg, the maximum permissible displacement of the main central axis of inertia of the rotor from the axis of rotation is 0.0203 mm. This value is due to the fact that if the displacement exceeds this value, the dynamic response of the bearing will exceed the set value of R = 400 N. Point C represents the center of mass of the rotor.

Solution to problem 17.4.15 from the collection of Kepe O.?.

This digital product is a solution to problem 17.4.15 from the collection of Kepe O.?. in technical mechanics. The solution is presented in a convenient format and includes a complete calculation that can be used for both practical purposes and training.

Problem 17.4.15 concerns the determination of the maximum permissible displacement of the main central axis of inertia of the rotor of an electric motor weighing 400 kg from the axis of rotation at a given rotation speed of 3000 rpm, so that the dynamic reaction of the bearing does not exceed the value R = 400 N. The solution to this problem can be useful for engineers involved in the design and operation of electric motors, as well as for students studying technical mechanics and its applications.

By purchasing this digital product, you receive a complete solution to problem 17.4.15 in a convenient format that can be used on any device. Beautiful html design ensures convenient navigation and ease of perception of information.

Don't miss the opportunity to purchase this useful solution to an engineering mechanics problem and use it in your projects or studies.

This product is a digital solution to problem 17.4.15 from the collection of Kepe O.?. in technical mechanics. The problem is to determine the maximum permissible displacement of the main central axis of inertia of the rotor of an electric motor weighing 400 kg from the axis of rotation at a given rotation speed of 3000 rpm, so that the dynamic reaction of the bearing does not exceed the value R = 400 N. The solution to this problem can be useful for engineers involved in design and operation of electric motors, as well as for students studying technical mechanics and its applications.

This digital product is presented in an easy to use format and includes full pricing. It can be used for both practical purposes and training. The solution is presented in a beautiful html design, providing convenient navigation and ease of perception of information. By purchasing this product, you receive a complete solution to problem 17.4.15 in a convenient format that can be used on any device. Don't miss the opportunity to purchase this useful solution to an engineering mechanics problem and use it in your projects or studies.

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Problem 17.4.15 from the collection of Kepe O.?. refers to the section "Thermodynamics and molecular physics" and is formulated as follows: "Two heat exchangers, each of which can operate as an evaporator or a condenser, are connected to each other. At the initial moment, one of them is filled with liquid, and the other with steam. Determine what part of the initial amount of heat was transferred from one heat exchanger to the other, if both heat exchangers worked until the saturated steam was completely condensed and turned into a liquid." To solve this problem it is necessary to use the laws of thermodynamics and the equations of state of matter. As a result of the solution, it is necessary to determine the proportion of heat transferred from one heat exchanger to another.

Solution to problem 17.4.15 from the collection of Kepe O.?. consists in determining the maximum permissible displacement e of the main central axis of inertia of the rotor of an electric motor weighing 400 kg from the axis of rotation at a known rotor speed, so that the dynamic response of the bearing does not exceed the value R = 400 N. Point C is the center of mass of the rotor.

To solve the problem, it is necessary to use the formula for calculating the dynamic reaction of the bearing:

R = mω^2e,

where m is the mass of the rotor, ω is the angular speed of rotation of the rotor, e is the maximum displacement of the main central axis of inertia of the rotor from the axis of rotation.

Let's rewrite the formula, expressing e:

e = R / (mω^2).

Substituting the known values, we get:

e = 400 / (400 * 3^2) = 0.0203 mm.

Thus, the answer to problem 17.4.15 from the collection of Kepe O.?. equal to 0.0203 mm.

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