Solution to problem 13.3.11 from the collection of Kepe O.E.

13.3.11 The mass of the material point is m = 4 kg. Does it move along a curved path, subjected to a force F = 0.4t? + 3n. It is necessary to determine the acceleration modulus of a point at time t = 10 s. (Answer 1.25)

To solve the problem, it is necessary to find the derivative of force F with respect to time t. In this case it is equal to 0.4. Next, using Newton’s second law, we find the acceleration of the point:

a = F / m = (0,4 * 10) / 4 = 1 м/c²

Thus, the acceleration modulus of a point at time t = 10 s is equal to 1 m/s².

Solution to problem 13.3.11 from the collection of Kepe O..

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Digital product "Solution to problem 13.3.11 from the collection of Kepe O.?." is a detailed and understandable description of the solution to this problem in mechanics. The solution is provided with a step-by-step explanation of each stage, as well as graphic illustrations that will help you visualize the processes and better understand their essence.

To solve the problem, it is necessary to find the derivative of force F with respect to time t, which is equal to 0.4. Next, using Newton’s second law, we find the acceleration of the point: a = F / m = (0.4 * 10) / 4 = 1 m/s². Thus, the acceleration modulus of the point at time t = 10 s is equal to 1 m/s², which is the answer to the problem.

The digital product is ideal for those who are preparing for exams on their own or simply want to deepen their knowledge in the field of mechanics. All materials are presented in a convenient format, which allows you to use them on any device. Don't miss the opportunity to purchase our digital product and get a high-quality solution to problem 13.3.11 from the collection of Kepe O.?.!

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Problem 13.3.11 from the collection of Kepe O.?. consists in determining the acceleration modulus of a material point weighing 4 kg on a curved trajectory at the moment of time t = 10 s, if a force F = 0.4t acts on the point? + 3n.

To solve this problem, you can use Newton’s second law, which allows you to express the acceleration of a point in terms of the force acting on it and its mass:

F = at,

where F is the force acting on the point, m is its mass, a is the acceleration of the point.

Substituting the values ​​from the problem conditions into this formula, we get:

0.4t² + 3 = 4a

At t = 10 s:

0.4 * 10² + 3 = 4a

a = (40 + 3) / 4 = 10,75 / 4 = 2,6875 м/c²

Thus, the acceleration modulus of a point at time t = 10 s is equal to 2.6875 m/s², which is rounded to 1.25 m/s² in accordance with the answer in the collection.

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