Solution to problem 13.2.8 from the collection of Kepe O.E.

13.2.8 A body with mass m = 20 kg falls vertically, air resistance force R = 0.04 v2.

Let's find the maximum speed of the body's fall.

Let us denote the maximum speed of falling body as V_max.

At maximum falling speed, the force of gravity is equal to the force of air resistance:

m*g = R

where g is the acceleration of gravity.

Let us express V_max from this equation:

V_max = √(m*g/R)

Let's substitute the values ​​and get:

V_max = √(20*9.81/0.04) ≈ 70.0 m/s

Thus, the maximum falling speed of the body is about 70.0 m/s.

Solution to problem 13.2.8 from the collection of Kepe O..

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Our digital product is a solution to problem 13.2.8 from the collection of Kepe O.?. The task is to determine the maximum speed of a body weighing 20 kg falling vertically in the presence of air resistance, which is determined by the formula R = 0.04 v2. Our solution includes a detailed analysis of the problem, a step-by-step solution and an answer to the question about the maximum speed of a body falling. The solution is presented in a beautiful html format, which makes it easy to use. By purchasing our digital product, you receive guaranteed quality and accuracy of solving the problem, and also save your time and effort. The answer to problem 13.2.8 from the collection of Kepe O.? is about 70.0 m/s. Don't miss the opportunity to easily solve this problem by purchasing our product.

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Problem 13.2.8 from the collection of Kepe O.?. consists in determining the maximum speed of a body weighing 20 kg falling vertically, taking into account the force of air resistance, which is determined by the formula R = 0.04 v2. To solve the problem, it is necessary to find a speed v at which the force of air resistance becomes equal to the force of gravity of the body. Thus, the equation of motion of the body will have the form: mg - 0.04v^2 = 0, where g is the acceleration of gravity.

By solving this equation, you can find the maximum speed of the body's fall, which is 70.0 m/s (accurate to one decimal place), as indicated in the problem.

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