When isobarically heating a gas at 100 K, 4.2 kD is required

When heating a gas at a constant pressure by 100 K, it is necessary to supply 4.2 kJ of heat, and when cooling the gas at a constant volume and halving the pressure, the gas releases 5.04 kJ of heat. The initial temperature of the gas during cooling at a constant volume is T2 = 400 K. To plot graphs of these processes in P – V coordinates, it is necessary to determine the Poisson’s ratio for a given gas.

When isobarically heating a gas at 100 K, 4.2 kJ of heat is required

Introducing a digital product that will help you understand thermodynamics! Our product contains information that when isobarically heating a gas at 100 K, 4.2 kJ of heat must be supplied.

This product will be useful for students and professionals in the field of physics and chemistry, as well as for anyone interested in science.

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Introducing a digital product that will help you understand thermodynamics! Our product contains information that when isobarically heating a gas by 100 K, it is necessary to supply 4.2 kJ of heat, and when isochorically cooling the gas releases 5.04 kJ of heat when the pressure is halved. The initial gas temperature during isochoric cooling is T2 = 400 K.

Using our digital product, you can plot these processes in P – V coordinates and determine the Poisson’s ratio for this gas. This product will be useful for students and professionals in the field of physics and chemistry, as well as for anyone interested in science.

You can purchase this digital product right now and start learning with pleasure! Also, if you have any questions about solving problem 20592, our product contains a detailed solution with a brief record of the conditions, formulas and laws used in the solution, a derivation of the calculation formula and the answer. If you need help, you can always contact him.

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This product is not a physical object, but rather a problem in the field of physics. The condition gives the parameters of isobaric and isochoric processes that can be used to calculate the Poisson's ratio for gas.

Poisson's ratio is defined as the ratio of the relative change in pressure to the relative change in volume during an adiabatic process. For a given gas, you can use the following ratio:

γ = - (ΔV/V) / (ΔP/P)

where ΔV/V is the relative change in volume, ΔP/P is the relative change in pressure.

From the conditions of the problem it is known that with isobaric heating of a gas by 100 K, 4.2 kJ of heat is required. Since the process is isobaric, we can use the formula:

Q = n * Cp * ΔT

where Q is the amount of heat, n is the amount of substance, Cp is the specific heat at constant pressure, ΔT is the change in temperature.

Since the amount of substance is constant, we can write:

Cp = Q / nΔT

Substituting the known values, we get:

Cp = 4.2 kJ / (n * 100 K)

Similarly, from the condition of isochoric gas cooling, Poisson's ratio can be expressed. Since the process is adiabatic, we can use the formula:

PV^γ = const

where P is pressure, V is volume, γ is Poisson's ratio.

When the pressure changes twice:

P' = P / 2

V' = V * (P/P')^(1/γ)

It is known that the initial gas temperature during isochoric cooling is T2 = 400 K. You can use the equation of state of an ideal gas to calculate the volume at the initial temperature:

PV = nRT

V = nRT / P

Substituting the known values, we get:

V = (nR / P) * T2

Knowing the initial volume and the volume when the pressure changes by a factor of two, we can express the relative change in volume and the relative change in pressure, and then find Poisson's ratio using the formula given above.

To construct graphs of processes in P – V coordinates, it is necessary to know the equation of state of the gas and the equation of processes (isobaric and isochoric). Based on the obtained values, you can construct the corresponding graphs.

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