A current of 10 A flows through a ring with a radius of 15 cm. In one

Let's imagine the task in the form of html code:

Task 31170

A current of 10 A flows through a ring with a radius of 15 cm. In the same plane as the ring there is a long straight insulated conductor, the current strength of which is 10 A. The conductor coincides with the tangent to the circle of the ring current. Find the magnetic field strength in the center of the ring for different directions of currents.

Hopefully:

• ring radius r = 15 cm = 0.15 m
• ring current I₁ = 10 A
• current strength in a straight conductor I₂ = 10 A

Find: magnetic field strength in the center of the ring for different directions of currents.

Answer:

We use the formula to calculate the magnetic field from the ring current:

Where B - magnetic induction, m₀ - magnetic constant, I₁ - current strength in the ring, r - radius of the ring, x - the distance from the center of the ring to the point at which the magnetic field is determined.

According to the assignment, the conductor coincides with the tangent to the circle of the ring current, so the direction of the currents in both cases coincides.

Let the point at which the magnetic field is determined be located on the axis of the ring in the center of the ring. Then the distance from the center of the ring to this point is zero, and the magnetic field is determined by the formula:

Substituting the known values, we get:

Answer: the magnetic field strength in the center of the ring for a given direction of currents is 2.12 µT.

If you change the direction of the current in the ring to the opposite, the sign of the magnetic field will also change.

Thus, with opposite directions of currents in the ring, the magnetic field at the center of the ring will have the opposite sign and be equal in magnitude to 2.12 μT.

Product description

We present to your attention the digital product "Calculation of the magnetic field strength in the center of the ring."

In this product you will find a detailed solution to problem 31170, in which you need to find the magnetic field strength in the center of a ring with a radius of 15 cm with a current of 10 A passing through the ring, and with a current of 10 A passing along the tangent to the circumference of the ring current.

The solution to the problem is presented in the form of html code, with a beautiful design and detailed commentary for each step of the solution. Also in the product description all the necessary formulas and laws used in solving the problem are indicated.

By purchasing this digital product, you will receive useful material for studying the physics of electromagnetism and improving your problem-solving skills.

Don't miss the opportunity to purchase a valuable product at a competitive price!

Product description:

We present to your attention the digital product "Calculation of the magnetic field strength in the center of the ring."

In this product you will find a detailed solution to problem 31170 in the physics of electromagnetism, in which it is necessary to find the magnetic field strength in the center of a ring with a radius of 15 cm with a current of 10 A passing through the ring, and with a current of 10 A passing along the tangent to the circumference of the ring current .

The solution to the problem is presented in the form of html code with a beautiful design and detailed commentary for each step of the solution. Also in the product description all the necessary formulas and laws used in solving the problem are indicated.

By purchasing this digital product, you will receive useful material for studying the physics of electromagnetism and improving your problem-solving skills. Don't miss the opportunity to purchase a valuable product at a competitive price! If you have any questions about the solution, write, we will try to help.

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Product description:

This product represents problem 31170, which consists of determining the magnetic field strength in the center of the ring for different directions of currents.

Task conditions:

A current of 10 A flows through a ring with a radius of 15 cm. In the same plane as the ring there is a long straight insulated conductor, the current strength of which is 10 A. The conductor coincides with the tangent to the circle of the ring current. Find the magnetic field strength in the center of the ring for different directions of currents.

To solve this problem, the laws of electrodynamics are used. In particular, Biot-Savart's law, which describes the magnetic field created by a current in a conductor, and Ampere's law, which allows one to calculate the magnetic field around a current.

Formula for calculating the magnetic field strength in the center of the ring with opposite directions of currents:

B = μ₀ * I / (2 * R)

where B is the magnetic field strength, μ₀ is the magnetic constant, I is the current, R is the radius of the ring.

Answer:

With opposite directions of currents, clockwise and counterclockwise, the magnetic field strength in the center of the ring is B = 3.33 * 10^-5 T.

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