During a game of gookodki, a bat weighing 1.3 kg was thrown

During a game of goading, a 1.3 kg bat was thrown horizontally at a height of 1.6 m from the ground with a speed of 7 m/s. During flight, the bit rotated relative to an axis perpendicular to the bit and passing through its middle vertically with a frequency of n=5 s^-1. It is necessary to determine the total mechanical energy of the bit.

To solve the problem, we will use the laws of conservation of energy. The total mechanical energy of a bit is equal to the sum of its kinetic and potential energy, as well as the energy of its rotational motion.

The kinetic energy of the bit is 1/2mv^2, where m is the mass of the bit, v is the speed of the bit. The potential energy of a bit is mgh, where g is the acceleration of gravity, h is the height of the bat throw. The rotational energy of the bit is 1/2Iω^2, where I is the moment of inertia of the bit relative to the axis of rotation, ω is the angular speed of rotation of the bit.

Let's find each component of energy. The kinetic energy of the bit is 1/21,3(7^2) = 31.85 J. Potential energy of the bit is 1.39,811.6 = 20.23 J. To find the rotational energy, it is necessary to find the moment of inertia of the bit relative to the axis of rotation. Since the bit rotates about an axis passing vertically through its middle, the moment of inertia is 1/12mL^2, where L is the length of the bit. Let the length of the bit be 1.2 m. Then the moment of inertia is 1/121,3(1.2^2) = 0.156 kgm^2. The angular speed of bit rotation ω is 2Pin, where n is the bit rotation frequency. Let n=5 s^-1, then ω=2Pi5 = 31.4 rad/s. So the rotational energy of the bit is 1/20.156*(31.4^2) = 76.67 J.

So, the total mechanical energy of the bit is equal to the sum of its kinetic, potential and rotational energy: 31.85 + 20.23 + 76.67 = 128.75 J. Answer: 128.75 J.

Digital product: "Solving the bat throwing problem"

Solving the bat throwing problem is a digital product designed for students and schoolchildren studying physics. This solution describes in detail the problem of throwing a bat with a mass of 1.3 kg during a game of goads. The solution contains a brief record of the conditions, formulas and laws used in solving the problem, the derivation of the calculation formula and the answer.

A beautifully designed solution to the problem includes a detailed description of each step of the solution and illustrations for a better understanding of the material. Our product will help you better understand physics material and prepare for exams.

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This product is a digital solution to the problem of throwing a 1.3 kg bat during a game of gorodki. The solution describes in detail the conditions of the problem, the formulas and laws used, the derivation of the calculation formula and the answer. A beautifully designed solution to the problem includes a detailed description of each step of the solution and illustrations for a better understanding of the material. The solution is intended for students and schoolchildren studying physics and will help them better understand the material and prepare for exams. You can purchase this product today, and if you have any questions about the solution, the author is ready to help.

This product is a digital product called "Solving the Bat Throwing Problem". It is intended for students and schoolchildren studying physics. The solution contains a detailed description of the problem of throwing a 1.3 kg bat during a game of goads, including a summary of the conditions, formulas and laws used in the solution. The solution contains the derivation of the calculation formula and the answer to the problem. In addition, the product contains illustrations and descriptions of each solution step for a better understanding of the material.

In this problem, you need to determine the total mechanical energy of a bat that was thrown horizontally at a height of 1.6 m from the ground with a speed of 7 m/s. During flight, the bit rotated relative to an axis perpendicular to the bit and passing through its middle vertically with a frequency of n=5 s^-1. To solve the problem, we will use the laws of conservation of energy.

The total mechanical energy of a bit is equal to the sum of its kinetic and potential energy, as well as the energy of its rotational motion. The kinetic energy of the bit is equal to 1/2mv^2, where m is the mass of the bit, v is the speed of the bit. The potential energy of the bat is equal to mgh, where g is the acceleration of gravity, h is the height of the bat throw. The rotational energy of the bit is equal to 1/2Iω^2, where I is the moment of inertia of the bit relative to the axis of rotation, ω is the angular speed of rotation of the bit.

To solve the problem it is necessary to find each component of energy. The kinetic energy of the bit is 1/21,3(7^2) = 31.85 J. Potential energy of the bit is 1.39,811.6 = 20.23 J. To find the rotational energy, it is necessary to find the moment of inertia of the bit relative to the axis of rotation. Since the bit rotates about an axis passing vertically through its middle, the moment of inertia is 1/12mL^2, where L is the length of the bit. Let the length of the bit be 1.2 m. Then the moment of inertia is 1/121,3(1.2^2) = 0.156 kgm^2. The angular speed of rotation of the bit ω is equal to 2πn, where n is the rotation frequency of the bit. Let n=5 s^-1, then ω=2π5 = 31.4 rad/s. So the rotational energy of the bit is 1/20.156*(31.4^2) = 76.67 J.

So, the total mechanical energy of the bit is equal to the sum of its kinetic, potential and rotational energy: 31.85 + 20.23 + 76.67 = 128.75 J. The answer to the problem is that the total mechanical energy of the bit is 128.75 J.

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a bat weighing 1.3 kg, designed for playing gorodki. The bat was thrown horizontally at a height of 1.6 m from the ground with a speed of 7 m/s. During flight, the bit rotated relative to an axis perpendicular to the bit and passing through its middle vertically with a frequency of n=5 s^-1. To determine the total mechanical energy of the bit, it is necessary to use the solution to problem 10321, which includes a brief recording of the conditions, formulas and laws, derivation of the calculation formula and the answer. If you have any questions about the solution, you can ask for help.

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