Solution to problem 9.2.6 from the collection of Kepe O.E.

9.2.6 Load speed 1 v = 0.5 m/s.

It is necessary to calculate the angular velocity of moving block 2 if its radius R = 0.1 m.

Answer: 2.5

In mechanical problems, it is important to understand the relationship between linear and angular velocity. The angular speed of the moving block 2 is related to the linear speed of the load 1 through the radius of the block 2: ω = v/R. Substituting the values, we get: ω = 0.5/0.1 = 5 rad/s. However, in this problem it is required to find the angular velocity of block 2 itself, and not of load 1, so the answer must be divided by the transmission coefficient equal to 2. Thus, the angular velocity of moving block 2 is equal to 2.5 rad/s.

Solution to problem 9.2.6 from the collection of Kepe O.?.

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Problem 9.2.6 from the collection of Kepe O.?. consists in determining the angular velocity of the moving block 2, if the speed of the load 1 and the radius of the block are known. According to the conditions of the problem, the speed of load 1 is 0.5 m/s, and the radius of moving block 2 is 0.1 m. It is necessary to find the angular velocity of block 2.

To solve the problem, we can use the formula for the relationship between linear and angular speed:

v = R * w,

where v is the linear speed, R is the radius of block 2, w is the angular speed.

Substituting known quantities, we get:

0.5 m/s = 0.1 m * w.

From here we find the angular velocity:

w = 0.5 m/s / 0.1 m = 5 rad/s.

Answer: the angular speed of the moving block 2 is 5 rad/s or 2.5 r/s (one revolution per second).

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