Solution to problem 2.4.43 from the collection of Kepe O.E.

Problem 2.4.43 is to determine the vertical component of the embedment reaction A of the cantilever beam in kN. It is known that the tension force of the cable F is 10 kN, and the angle is? between the cable and the horizon is 30°. The answer to the problem is 5.0 kN.

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We offer to purchase a unique digital product - the solution to problem 2.4.43 from the collection of Kepe O.?. This task is to determine the vertical component of the embedment reaction A of the cantilever beam in kN. In the problem it is known that the tension force of the cable F is 10 kN, and the angle between the cable and the horizon is 30°. The answer to the problem is 5.0 kN.

Our digital product is a complete and detailed solution to this problem. It contains all the necessary calculations and explanations, which will help you quickly and easily understand the material. The solution is designed in a beautiful HTML format, which makes it convenient and attractive to read. You can easily find the information you need and quickly jump to the sections you need.

When purchasing our digital product, you can be sure of its high quality and accuracy. The solution to the problem has been tested by experienced specialists and meets high standards. This useful product will help you greatly simplify your learning process. Don't miss the opportunity to purchase it and get a detailed solution to problem 2.4.43 from the collection of Kepe O.?.

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Embedment A of the cantilever beam is subjected to a cable tension force F = 10 kN, forming an angle ? = 30° with the horizontal. It is necessary to determine the vertical component of the embedment reaction A in kN.

To solve the problem, we use the equilibrium condition of the body: the sum of all external forces acting on the body is equal to zero.

In this case, taking into account only the vertical component, we can write the equation:

R - F*sin(30°) = 0

where R is the vertical component of the embedding reaction A.

Solving the equation, we get:

R = F*sin(30°) = 10kN * 0.5 = 5.0 kN

Thus, the vertical component of the embedment reaction A of the cantilever beam is equal to 5.0 kN.

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