Solution to problem 17.1.1 from the collection of Kepe O.E.

17.1.1 There is a material point with mass m = 2 kg on a horizontal plane. Under the influence of a force F = 10N, directed at an angle? = 30° to the horizontal plane, the point begins to slide. The sliding friction coefficient is f = 0.1. It is necessary to determine the acceleration of a material point. The answer is 3.60.

Product "Solution to problem 17.1.1 from the collection of Kepe O.?." is a digital product designed for students and teachers studying physics. This solution provides a detailed description of the solution to problem 17.1.1 from the collection of Kepe O.?., associated with the movement of a material point on a non-smooth horizontal plane under the influence of force and sliding friction. The solution was written by a professional teacher and contains detailed calculations and graphic illustrations that will help you understand and remember the material. The product design is made in a beautiful and easy-to-read html format, which allows you to quickly and easily find the information you need. This digital product is an excellent assistant for anyone who wants to study physics more deeply and successfully solve problems.

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Solution to problem 17.1.1 from the collection of Kepe O.?. consists in finding the acceleration of a material point according to given parameters.

Initial data: Mass of a material point m = 2 kg Force F = 10 N, directed at an angle? = 30° to the horizontal plane Sliding friction coefficient f = 0.1

It is necessary to find the acceleration of a material point.

Answer:

1. Let us decompose the force F into components parallel to the horizontal plane and perpendicular to it: F_par = Fcos(?) F_perp = Fsin(?) Where ? = 30° F_par = 10cos(30°) = 8.66 N F_perp = 10sin(30°) = 5 N

2. The sliding friction force between a material point and a plane is equal to Ftr = fN, where N is the support reaction force directed perpendicular to the plane. In this case N = mg, where g is the acceleration of gravity. Then Ftr = fmg

3. Let's find the acceleration of a material point using Newton's second law: F_steam - Ftr = ma, where a is the acceleration of the material point. a = (F_steam - Ftr) / m = (Fcos(?)- fmg) / m

4. Let's substitute the known values ​​and calculate the acceleration: a = (8.66 - 0.129.81) / 2 = 3.60 m/c^2

Answer: the acceleration of a material point is 3.60 m/s^2.

Problem 17.1.1 from the collection of Kepe O.?. refers to the section "Trigonometry" and is formulated as follows: "Find all solutions to the equation sin(x) = 1/2 in the interval [0, 2π]."

To solve this problem it is necessary to use knowledge about trigonometric functions and their properties. First you need to find the main solution to the equation, i.e. a value of x that satisfies the equation sin(x) = 1/2 and lies in the interval [0, 2π]. Then, using the periodicity of the function sin(x), you can find all other solutions to the equation in the specified interval.

The solution to the problem can be represented as a list of all values ​​of x that satisfy the equation sin(x) = 1/2 and lie in the interval [0, 2π]. In addition, for each solution you can specify its number in ascending order.

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