Solution to problem 15.1.17 from the collection of Kepe O.E.

15.1.17. A pair of forces with a constant moment M = 10 N•m is applied to drum 1. Cylinder 2 with a mass of m2 = 10 kg moves without sliding, with a rolling friction coefficient of ? = 0.01 m. It is necessary to determine the work of external forces of the system when turning drum 1 by 10 revolutions. The answer to the problem is 567.

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The digital product that we offer in our store contains the solution to problem 15.1.17 from the collection of Kepe O.?. This problem is that a pair of forces with a constant moment M = 10 N•m is applied to drum 1, and cylinder 2 with mass m2 = 10 kg moves without sliding with a rolling friction coefficient μ = 0.01 m. It is necessary to determine the work of external forces system when turning drum 1 by 10 revolutions.

Our digital product contains a beautifully designed html file that describes the problem in detail and provides a step-by-step solution to the problem with explanations. At the end of the file you will find the answer to the problem, which is 567.

By purchasing our digital product, you get an excellent tool for learning and improving your knowledge in the field of physics. We guarantee you high quality product and fast delivery. Don't miss the opportunity to purchase the solution to problem 15.1.17 from the collection of Kepe O.?. today!

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Product description:

Solution to problem 15.1.17 from the collection of Kepe O.?.

In this problem, we consider a system consisting of drum 1 and cylinder 2. A pair of forces with a constant moment M = 10 N •m is applied to drum 1. Cylinder 2 with mass m2 = 10 kg rolls without sliding, rolling friction coefficient μ = 0.01 m. It is necessary to determine the work of the external forces of the system when turning drum 1 by 10 revolutions.

To solve the problem it is necessary to use the laws of dynamics of rotational motion. The work of external forces in this case is defined as the product of the moment of force and the angle of rotation. In this case, the rotation angle is 10 revolutions, that is, 20π radians.

Solving the problem comes down to finding the moment of friction forces and the moment of inertia of the cylinder. The work done by external forces can then be determined using the formula:

A = ΔE = ΔK + ΔU = ΔΔθ,

where A is the work of external forces, ΔE is the change in the energy of the system, ΔK is the change in kinetic energy, ΔU is the change in potential energy, Στ is the sum of the moments of forces acting on the system, Δθ is the angle of rotation.

As a result of the calculations, it turns out that the work of the external forces of the system when rotating drum 1 by 10 revolutions is equal to 567 J. The answer coincides with that indicated in the task.

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