Solution to problem 14.2.22 from the collection of Kepe O.E.

It is necessary to determine the modulus of momentum of a homogeneous rod with length AB = 1 m and mass m = 5 kg.

At a given moment in time, the rod is performing plane-parallel motion with a speed of point A equal to 4 m/s and an angular speed of ? = 4 rad/s.

To solve the problem we use the formula:

Momentum L = m * v * l + I * ω, where

• L is the amount of movement;
• m is the mass of the rod;
• v is the speed of the center of mass of the rod;
• l is the length of the rod;
• I - moment of inertia of the rod;
• ω is the angular velocity of the rod.

First, let's find the moment of inertia of the rod relative to the axis passing through its center of mass:

I = m * l^2 / 12

We substitute the values ​​and get:

I = 5 * 1^2 / 12 = 0.4166 (kg * m^2)

Now we can find the amount of motion:

L = m * v * l + I * ω = 5 * 4 * 1 + 0.4166 * 4 = 30 (kg * м/с)

Answer: 30.

Solution to problem 14.2.22 from the collection of Kepe O..

that digital product is a solution to problem 14.2.22 from the collection of problems in physics by Kepe O.. In the problem it is necessary to determine the modulus of momentum of a homogeneous rod with a length of 1 m and a mass of 5 kg, which performs plane-parallel motion with a speed of point A equal to 4 m/s and angular velocity 4 rad/s.

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Product - solution to problem 14.2.22 from the collection of Kepe O.?. The problem is to determine the modulus of momentum of a homogeneous rod with a length of 1 m and a mass of 5 kg, which performs plane-parallel motion at the moment of time when its angular velocity is equal to 4 rad/s, and the speed of point A is equal to 4 m/s. Solving the problem leads to an answer of 30.

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