13.3.20 In the horizontal plane, a material point M with a mass m = 1.6 kg begins to move from a state of rest along a circle of radius R = 12 m under the influence of a force F = 0.2t. It is necessary to determine the velocity of a point at time t = 18 s if the angle between the velocity vector and the direction of the force is a constant angle of 25° (Answer 3.38).
This digital product is the solution to problem 13.3.20 from the collection of Kepe O.?. in physics. The solution is presented in the form of a detailed presentation with a step-by-step description of the actions required to obtain an answer.
The task is to determine the speed of a point moving in a horizontal plane along a circle of radius 12 m at a time of 18 seconds under the influence of a force varying according to the law F = 0.2t. The angle between the velocity vector and the direction of the force is a constant angle of 25°.
This solution can be useful for physics students and teachers, as well as for anyone interested in solving problems in the field of science and technology.
This digital product is a solution to problem 13.3.20 in physics from the collection of Kepe O.?. The solution is presented in the form of a detailed layout with a description of each step that is necessary to obtain the answer. The task is to determine the speed of a point moving in a horizontal plane along a circle of radius 12 m at a time of 18 seconds under the influence of a force varying according to the law F = 0.2t. The angle between the velocity vector and the direction of the force is a constant angle of 25°. The solution may be useful for physics students and teachers, as well as for anyone interested in solving problems in the field of science and technology. Product features include a detailed solution to the problem with a beautiful design in HTML format, which makes it easy to use. The price of the product is 50 rubles.
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Solution to problem 13.3.20 from the collection of Kepe O.?. as follows:
Given: mass of the material point M, m = 1.6 kg; radius of the circle, R = 12 m; force acting on point F = 0.2t; time, t = 18 s; the angle between the velocity vector and the direction of the force, α = 25°.
You need to find the speed of a point at time t.
Answer:
F = at,
where F is the force acting on the point, m is the mass of the point, a is its acceleration.
We substitute known values:
0,2t = 1,6a
a = 0,125t м/c²
v = ωR,
where v is linear speed, ω is angular speed, R is the radius of the circle.
Angular velocity is defined as:
ω = v/R.
Thus, v = ωR = (α/180°)πR/t.
We substitute known values:
v = (25°/180°)π ⋅ 12 m/18 s = 3.38 m/s.
Answer: the speed of the point at time t = 18 s is 3.38 m/s.
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