Solution to problem 2.5.8 from the collection of Kepe O.E.

Consider the problem of weights on an inclined plane. Let there be two loads on the plane: load 1 with a mass of 10 kg and load 2 with a mass m, connected by a weightless thread. Load 1 is located at a distance of 5 m from the top of the plane, and load 2 is located at a distance of 10 m from the top of the plane. The coefficient of sliding friction between the loads and the plane is 0.3.

In order for load 1 to remain at rest on an inclined plane, it is necessary that the friction force acting on it be equal to the projection of gravity on the axis perpendicular to the plane. Thus, we can write the equation:

100Н = m*g*sin(θ) - f*m*g*cos(θ),

where g is the acceleration of gravity, θ is the angle of inclination of the plane, f is the coefficient of sliding friction.

From this equation we can express the maximum mass of load 2:

m = (100Н + f*m*g*cos(θ)) / (g*sin(θ))

Having solved this equation for m, we get the answer: the maximum mass of load 2 should be equal to 76.0 kg.

Solution to problem 2.5.8 from the collection of Kepe O.?.

This digital product is a solution to problem 2.5.8 from the collection of problems by Kepe O.?. in physics. This solution describes in detail what the largest weight of load 2 must be in order for load 1 to remain at rest on an inclined plane under given conditions. The solution to this problem will be useful to students and teachers of physics, as well as to anyone interested in this topic.

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Product description: this is a digital product that is a solution to problem 2.5.8 from the collection of problems by Kepe O.?. in physics. This solution describes in detail what the largest weight of load 2 must be in order for load 1 to remain at rest on an inclined plane under given conditions. The solution to this problem will be useful to students and teachers of physics, as well as to anyone interested in this topic. The page is beautifully designed in a minimalist style using neutral colors and a clear layout for ease of reading. The price of this digital product is 99 rubles.

The digital product that you are going to buy for 99 rubles is a solution to problem 2.5.8 from the collection of problems in physics by Kepe O.?. electronic.

The problem considers two loads on an inclined plane: load 1 with a mass of 10 kg and load 2 with a mass m, connected by a weightless thread. Load 1 is located at a distance of 5 m from the top of the plane, and load 2 is located at a distance of 10 m from the top of the plane. In order for load 1 to remain at rest on an inclined plane, it is necessary that the friction force acting on it be equal to the projection of gravity on the axis perpendicular to the plane. The task is to determine the largest mass of load 2 at which load 1 will remain at rest on an inclined plane under given conditions.

The solution to the problem is described in detail in the digital product. From the equation that describes the forces acting on the load system, we can express the maximum mass of load 2 at which load 1 will remain at rest on an inclined plane under given conditions. The solution to this problem will be useful to students and teachers of physics, as well as to anyone interested in this topic.

The digital product is designed in a minimalist style using neutral colors and a clear layout for ease of reading. The cost of this digital product is 99 rubles.

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Solution to problem 2.5.8 from the collection of Kepe O.?. is associated with determining the largest weight of load 2 that can be placed on an inclined plane so that load 1 weighing 100 N remains at rest. In this case, the sliding friction coefficient is 0.3.

To solve the problem, it is necessary to use the condition of equilibrium of forces acting on loads on an inclined plane. In this case, the forces acting on the loads can be divided into two components: parallel and perpendicular to the plane. The perpendicular force is considered to be the force of gravity, and the parallel force must be calculated from the friction force formula.

Thus, the sum of the parallel forces on the loads must be zero for load 1 to remain at rest. Using the coefficient of sliding friction and the angle of inclination of the plane, we can calculate the maximum weight of load 2 that can be placed on the plane so that load 1 remains at rest.

Having solved this problem, we get the answer 76.0 N.

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