Solution to problem 17.1.17 from the collection of Kepe O.E.

17.1.17 In the horizontal plane there is a non-smooth guide of radius r = 0.5 m, along which a material point with mass m = 1.5 kg slides. The point moves at a constant speed v = 2 m/s and under the influence of force F. Sliding friction is characterized by a coefficient f = 0.15. It is necessary to determine the force modulus F. Answer: 2.85.

Explanation: this problem is related to the study of the movement of a material point on a non-smooth surface. In this case, in order for a material point to move at a constant speed, it is necessary to compensate for the sliding friction force. The sliding friction force is directed opposite to the movement of the point and its module is equal to the product of the friction coefficient and the support reaction force. In order to determine the magnitude of the force F, it is necessary to use Newton's second law for the projection onto the x-axis, taking into account that the sum of the forces along this axis is zero, since the point moves at a constant speed. By solving the equation, you can find F.

Solution to problem 17.1.17 from the collection of Kepe O.?. is a digital product that represents a solution to a physics problem. This product is available for purchase in the digital store and will be useful for those studying physics or preparing for exams.

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This product is a solution to problem 17.1.17 from the collection of Kepe O.?. in physics in Russian. The problem considers the movement of a material point with a mass of 1.5 kg along a non-smooth guide of radius 0.5 m in the horizontal plane. The point moves at a constant speed of 2 m/s and under the influence of force F. The sliding friction coefficient is 0.15. It is necessary to determine the force modulus F.

To solve the problem, it is necessary to take into account that in order for a material point to move at a constant speed, it is necessary to compensate for the sliding friction force. The sliding friction force is directed opposite to the movement of the point and its module is equal to the product of the friction coefficient and the support reaction force. In order to determine the magnitude of the force F, it is necessary to use Newton's second law for the projection onto the x-axis, taking into account that the sum of the forces along this axis is zero, since the point moves at a constant speed. By solving the equation, you can find F.

The digital product is presented in a beautiful html format, which allows you to conveniently view and study the material. By purchasing this product, you receive a unique product that will help you better understand physical laws and apply them in practice.


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Product description:

Solution to problem 17.1.17 from the collection of Kepe O.?. is a detailed description of a method for solving a physical problem associated with the movement of a material point along a non-smooth guide. In the problem, it is necessary to determine the modulus of the force F acting on a point if its mass, constant speed and sliding friction coefficient are known.

Solving the problem consists of the following steps:

  1. Determination of all known quantities: mass of a material point (m = 1.5 kg), constant speed (v = 2 m/s), guide radius (r = 0.5 m) and sliding friction coefficient (f = 0.15).

  2. Calculation of the friction force acting on a point. To do this, it is necessary to use the sliding friction force formula: Ftr = fN, where N is the support reaction force, equal in this case to the weight of the material point N = mg.

  3. Determination of the components of force F in the direction of the tangent and normal to the guide. According to the conditions of the problem, a material point moves along a guide with a constant speed, therefore, according to Newton’s second law, the sum of all forces acting on the point must be equal to zero.

  4. Finding the modulus of force F using the formula: F = sqrt(Ft^2 + Fn^2), where Ft is the component of force F in the direction tangent to the guide, Fn is the component of force F in the direction of the normal to the guide.

The final answer to the problem is 2.85 N.


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