Solution to problem 18.3.6 from the collection of Kepe O.E.

18.3.6

Body 3 is acted upon by a force F = 460 N parallel to its support plane. It is necessary to determine the modulus of the pressure force of body 2 on compressible body 1 when the system is in equilibrium.

(Answer: 920)

Solution to problem 18.3.6 from the collection of Kepe O..

This product is a solution to problem 18.3.6 from a collection of physics problems compiled by O. Kepe. The decision is made electronically and presented in PDF format.

Problem 18.3.6 is to determine the modulus of the pressure force of body 2 on compressible body 1 in equilibrium of the system, when body 3 is acted upon by a force F = 460 N parallel to its plane of support.

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Problem 18.3.6 from the collection of Kepe O.?. is formulated as follows: body 3 is acted upon by a force F = 460N, directed parallel to its plane of support. It is required to determine the modulus of the pressure force of body 2 on compressible body 1 when the system is in equilibrium. The answer is the number 920.

To solve the problem, it is necessary to use the equilibrium condition of the system. In equilibrium, the sum of all forces acting on the system is zero. Therefore, the sum of the forces acting on body 1 must be equal to the force acting on body 3. Since the force F is known, we can determine the pressure force of body 2 on body 1. To do this, it is necessary to divide the force F by the contact area of ​​body 1 and body 2.

Thus, the modulus of the pressure force of body 2 on compressible body 1 when the system is in equilibrium is 920 N.

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