Solution to problem 15.5.4 from the collection of Kepe O.E.

While lowering a load of mass m = 4 kg, a cylinder of radius R = 0.4 m rotates with the help of a thread. The moment of inertia of the cylinder relative to the axis of rotation is I = 0.2 kg • m2. With a load speed v = 2 m/s, it is necessary to determine the kinetic energy of the system of bodies. The answer to the problem is 10.5.

The solution to this problem can begin by calculating the kinetic energy of the load, which is equal to K = mv^2/2 = 4 * 2^2 / 2 = 8 J. Then it is necessary to determine the kinetic energy of the cylinder, which rotates around its axis. The kinetic energy of the cylinder is determined by the formula K = I * w^2 / 2, where w is the angular velocity of rotation of the cylinder. The angular velocity is calculated from the condition that the linear velocity at the point of contact of the thread with the cylinder is equal to the speed of the load v. Thus, w = v / R. Substituting the values ​​​​into the formula for the kinetic energy of the cylinder, we get K = I * v^2 / (2 * R^2) = 0.2 * 2^2 / (2 * 0.4^ 2) = 2.5 J. So, the total kinetic energy of the system of bodies at the moment of time when the speed of the load v = 2 m/s is equal to the sum of the kinetic energies of the load and the cylinder, i.e. K = 8 + 2.5 = 10.5 J.

Solution to problem 15.5.4 from the collection of Kepe O.?.

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Inside you will find a complete solution to Problem 15.5.4, which will help you better understand the principles of physics and learn how to apply them in practice. Beautiful design in html format will make reading the material even more convenient and enjoyable.

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• File with the solution to problem 15.5.4 from the collection of Kepe O.?. in PDF and HTML formats

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A digital product is offered in PDF and HTML formats, containing a complete solution to problem 15.5.4 from the collection of Kepe O.?. in physics. The problem considers a system consisting of a load weighing 4 kg and a cylinder of radius 0.4 m, the moment of inertia of which relative to the axis of rotation is 0.2 kg•m^2. With a load speed v = 2 m/s, it is necessary to determine the total kinetic energy of the system of bodies.

Inside the digital product, in a convenient and beautiful design, there is a detailed solution to the problem, including the calculation of the kinetic energy of the load and the cylinder, as well as their sum. The solution is made in accordance with the principles of physics and allows you to better understand this area of ​​​​knowledge.

The product has a file size of 2 MB and is compatible with all PDF and HTML file readers and requires internet access to download. In addition, the quality of the product provided is guaranteed, and technical support is always ready to help if you encounter problems downloading or opening a file.

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The product in this case is the solution to problem 15.5.4 from the collection of Kepe O.?. The task is to determine the kinetic energy of a system of bodies at the moment of time when the speed of the load is 2 m/s. The following parameters are given in the problem: mass of the load m = 4 kg, radius of the cylinder R = 0.4 m, moment of inertia of the cylinder relative to the axis of rotation I = 0.2 kg • m2. It is also known that the weight is lowered down and causes the cylinder to rotate with the help of a thread.

To solve the problem it is necessary to use the laws of conservation of energy and angular momentum. At the initial stage, you should determine the angular velocity of the cylinder, which will be equal to the speed of the load divided by the radius of the cylinder. The kinetic energy of the load and the cylinder can then be determined using the appropriate formulas. Their sum will be the desired kinetic energy of the system of bodies.

Ultimately, having solved this problem, we get the answer 10.5.

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