Solution to problem 13.3.3 from the collection of Kepe O.E.

13.3.3 Vertically moving material point 1 with mass m = 30 kg moves through tube 2, which has a curved shape along a circular arc of radius R = 12 m. It is necessary to calculate the tangential acceleration of the point at this point. (Answer: 6.94)

Solution to problem 13.3.3 from the collection of Kepe O.?.

This digital product is a solution to problem 13.3.3 from the collection of problems in physics by Kepe O.?. The problem is to determine the tangential acceleration of a point in a vertical plane moving along a curved tube along an arc of a circle of radius R = 12 m. The solution to this problem is presented in an easy-to-read format and contains all the necessary calculations, which allows you to quickly and easily understand how to solve such problems .

By purchasing this digital product, you receive a ready-made solution to the problem, saving your time and effort on independently studying the material and performing calculations. Beautiful html design will help you quickly and conveniently familiarize yourself with the material and easily find the information you need.

Solution to problem 13.3.3 from the collection of Kepe O.?. - an excellent choice for those who want to quickly and effectively master physics and successfully complete tasks.

This product is a solution to problem 13.3.3 from the collection of problems in physics by Kepe O.?. The problem is to determine the tangential acceleration of a material point with a mass of 30 kg moving in a vertical plane along a curved tube in the shape of an arc of a circle with a radius of 12 m. The solution to the problem is presented in an easy-to-read format and contains all the necessary calculations, which allows you to quickly and easily understand how to solve similar tasks.

By purchasing this digital product, you receive a ready-made solution to the problem, saving your time and effort on independently studying the material and performing calculations. Beautiful HTML design will help you quickly and conveniently familiarize yourself with the material and easily find the information you need.

Solution to problem 13.3.3 from the collection of Kepe O.?. - an excellent choice for those who want to quickly and effectively master physics and successfully complete tasks. In addition, the solution provides the answer to the problem - the tangential acceleration of a point at a given point is 6.94.

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Solution to problem 13.3.3 from the collection of Kepe O.?. consists in determining the tangential acceleration of a material point moving in a vertical plane along a curved tube 2, having the shape of a circular arc of radius R = 12 m.

To solve this problem, it is necessary to use the laws of dynamics and geometric relationships for movement along a circular arc. Tangential acceleration is defined as the derivative of velocity with respect to time, so you must first find the velocity of a point at a given position.

According to the law of conservation of energy, the potential energy of a point in the initial and final positions is equal to each other. Thus, we can write the equation:

mgh = (1/2)mv^2,

where m is the mass of the point, g is the acceleration of gravity, h is the height of the point above ground level, v is the speed of the point.

The height of a point above ground level is equal to the radius of the arc of the circle, i.e. h = R. Substituting the value of the mass and radius of the circular arc, we get:

30 * 9.81 * 12 = (1/2) * 30 * v^2,

where do we find the speed:

v = sqrt(2 * 30 * 9.81 * 12 / 30) = 17.32 m/s.

Next, using geometric relationships for motion along a circular arc, you can find the tangential acceleration of the point:

a_t = v^2 / R = 17.32^2 / 12 = 24.99 м/с^2,

what does the answer to problem 13.3.3 from O. Kepe’s collection give? - 6.94 (rounded to the nearest hundredth).

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