Solution C3-12 (Figure C3.1 condition 2 S.M. Targ 1989)

Solution to problem C3-12, shown in Figure C3.1, condition 2 from the book by S.M. Targa 1989, consists in determining the forces in six weightless rods, hinged to each other in two nodes and attached with other ends to fixed supports A, B, C, D. The nodes are located at the vertices H, K, L or M of a rectangular parallelepiped in according to the table data. In the first node of each column of the table, a force P = 200 N is applied, and in the second node a force Q = 100 N is applied. The angles that the force P forms with the positive directions of the coordinate axes x, y, z are equal to α1 = 45°, β1 = respectively 60°, γ1 = 60°, and force Q forms angles α2 = 60°, β2 = 45°, γ2 = 60° with the same axes. The directions of the x, y, z axes for all figures are shown in Figure SZ.0. The faces of a parallelepiped parallel to the xy plane are squares. The diagonals of the other side faces form an angle φ = 60° with the xy plane, and the diagonal of the parallelepiped forms an angle θ = 51° with this plane. To solve the problem, it is necessary to draw a drawing of the bars and nodes in accordance with the conditions of the problem, as shown in Figure C3.10. In Figure NW. Figure 1 shows an example of a drawing for the case when the nodes are located at points L and M, and the rods are LM, LA, LB; MA, MS, MD. Also in Figure NW. 1 shows the angles φ and θ. After constructing the drawing, you can determine the forces in the rods.

Our digital goods store offers you to purchase a unique product - a solution to problem C3-12, shown in Figure C3.1, condition 2 from the book by S.M. Targa 1989. This digital product contains a detailed solution to the problem, including a drawing of rods and nodes in accordance with the conditions of the problem, as well as determination of the forces in the rods. All information is presented in a beautiful and clear html format, which ensures convenient and easy reading and understanding of the material. By purchasing this digital product, you receive a unique product that will help you better understand the topic and successfully solve similar problems.

Our digital goods store offers you a unique product - a solution to problem C3-12, shown in Figure C3.1 condition 2 from the book by S.M. Targa 1989. The solution lies in determining the forces in six weightless rods, hingedly connected to each other in two nodes and attached with other ends to fixed supports A, B, C, D. The nodes are located at the vertices H, K, L or M of a rectangular parallelepiped in accordance with the data tables. In the first node of each column of the table, a force P = 200 N is applied, and in the second node a force Q = 100 N is applied. The angles that the force P forms with the positive directions of the coordinate axes x, y, z are equal to α1 = 45°, β1 = respectively 60°, γ1 = 60°, and force Q forms angles α2 = 60°, β2 = 45°, γ2 = 60° with the same axes. The faces of a parallelepiped parallel to the xy plane are squares. The diagonals of the other side faces form an angle φ = 60° with the xy plane, and the diagonal of the parallelepiped forms an angle θ = 51° with this plane.

Our product contains a detailed solution to the problem, including a drawing of rods and nodes in accordance with the conditions of the problem, as well as determination of the forces in the rods. All information is presented in a beautiful and clear html format, which ensures convenient and easy reading and understanding of the material.

By purchasing this digital product, you receive a unique product that will help you better understand the topic and successfully solve similar problems. Our store guarantees high product quality and fast delivery.


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Solution C3-12 is a structure of six weightless rods, hingedly connected at the ends to each other in two nodes and attached to fixed supports A, B, C, D. The nodes are located at the vertices H, K, L or M of a rectangular parallelepiped. In the figures, rods and nodes are not shown and should be depicted as solving the problem according to the table data.

At the node, which is indicated first in each column of the table, a force P = 200 N is applied; in the second node, a force Q = 100 N is applied. The force P forms angles equal to α1 = 45°, β1 = 60°, γ1 = 60° with the positive directions of the coordinate axes x, y, z, respectively, and the force Q forms angles α2 = 60 °, β2 = 45°, γ2 = 60°.

The faces of a parallelepiped parallel to the xy plane are squares. The diagonals of the other side faces form an angle φ = 60° with the xy plane, and the diagonal of the parallelepiped forms an angle θ = 51° with this plane.

To solve the problem, it is necessary to determine the forces in the rods. Figure C3.10 shows how the drawing should look if, according to the conditions of the problem, the nodes are located at points L and M, and the rods are LM, LA, LB; MA, MS, MD. The angles φ and θ are also shown there.


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