End B of a uniform beam weighing 100 kN, fixed

Let's solve Let's consider the problem: A uniform beam weighing 100 kN rests on a smooth wall, fixed in hinge A. It is necessary to find the pressure of the beam on the wall in kN if the angle between the beam and the wall is 60°. Solution: From the conditions of the problem it follows that the force with which the beam acts on the wall is directed perpendicular to the surface of the wall. Thus, to determine the pressure on the wall, it is necessary to decompose the force vector into components parallel and perpendicular to the wall. Let's decompose the force vector into components: $$F_{\parallel}=F\cdot \sin a=100\cdot \sin 60^\circ\approx 86.6\text{ kN}$$ Thus, the pressure of the beam on the wall is about 86.6 kN.

This product is not a product in the full sense of the word, but rather describes a situation from a mechanics problem. Thus, a description of the product is not possible in this case. If you have a specific question about a task, I can try to help solve it.

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Product description:

A homogeneous beam weighing 100 kN is proposed, fixed in hinge A and resting on a smooth wall at an angle a=60°. To determine the pressure of a beam on a wall, you must use the following formulas and laws:

1. The law of equilibrium of a rigid body: the sum of all forces acting on a body is equal to zero.
2. Law of support reaction: the reaction of the support on the body is equal to the force acting on the support.
3. The formula for determining the pressure on a wall: P = F/S, where P is pressure, F is the force acting on the wall, S is the area over which this force acts.

Taking into account these laws and formulas, the following calculation formula can be derived to determine the pressure of the beam on the wall:

P = (W * sin a) / cos a * L,

where W is the weight of the beam, a is the angle between the beam and the wall, L is the length of the beam.

Substituting known values, we get:

P = (100 кН * sin 60°) / cos 60° * L ≈ 57.7 кН/L.

Thus, the pressure of the beam on the wall is about 57.7 kN for each meter of beam length. If you have any questions about the solution, please contact me, I will try to help.

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